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Leviafan [203]
1 year ago
13

John swims 2.5 miles and sees a total of 12 fishes if he swims 8 miles how many fish will he see

Mathematics
1 answer:
Zolol [24]1 year ago
5 0

Answer:

Step-by-step explanation:

2.5 miles = 12 fishes

Therefore,

8 miles = 12*8/2.5=96/2.5= 960/25=38.4 fishes

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Solve by factoring:<br> 5t=t ^2
elena-14-01-66 [18.8K]

Answer:

t=0 and t=5

Step-by-step explanation:

5t = t^2

Subtract 5t from each side

5t-5t = t^2 -5t

0= t^2 -5t

Factor out a t

0= t(t-5)

Using the zero product property

t=0  and t-5 =0

t=0  and  t-5+5=0+5

t=0 and t=5

7 0
3 years ago
The answer is red show step by step of the pro tem to get the answer
miskamm [114]

In order to rationalize the denominator of each expression, we need to multiply the expression by the same radical in the denominator, this way we can remove the radical from the denominator.

9)

\frac{5\sqrt{4}}{\sqrt{3}}(\cdot\sqrt{3})=\frac{5\sqrt{4}\sqrt{3}}{(\sqrt{3})^2}=\frac{5\cdot2\cdot\sqrt{3}}{3}=\frac{10\sqrt{3}}{3}

10)

-\frac{5}{3\sqrt{2}}(\cdot\sqrt{2})=-\frac{5\sqrt{2}}{3(\sqrt{2})^2}=-\frac{5\sqrt{2}}{3\cdot2}=-\frac{5\sqrt{2}}{6}

11)

\frac{2\sqrt{3}}{4\sqrt{5}}(\cdot\sqrt{5})=\frac{2\sqrt{3}\sqrt{5}}{4(\sqrt{5})^2}=\frac{2\sqrt{15}}{4\cdot5}=\frac{\sqrt{15}}{2\cdot5}=\frac{\sqrt{15}}{10}

12)

\frac{\sqrt{5}}{\sqrt{2}}(\cdot\sqrt{2})=\frac{\sqrt{5}\sqrt{2}}{(\sqrt{2})^2}=\frac{\sqrt{10}}{2}

3 0
1 year ago
1. Point C lies on BD. Draw a diagram and label the parts. If BC = 52.39 mm and CD = 21.83 mm, what is
kondaur [170]

Answer:

74.32

Step-by-step explanation:

Add the two together, and you have your answer b/c it's asking for the total length of the line

4 0
3 years ago
Read 2 more answers
Geometry!!!!!!!!!!!!!!!!!!!!!!!!
Stella [2.4K]

<u>Given</u>:

Given that O is the center of the circle.

The radius of the circle is 3 m.

The measure of ∠AOB is 30°

We need to determine the length of the major arc ACB

<u>Measure of major ∠AOB:</u>

The measure of major angle AOB can be determined by subtracting 360° and 30°

Thus, we have;

Major \ \angle AOB=360-30

Major \ \angle AOB=330^{\circ}

Thus, the measure of major angle is 330°

<u>Length of the major arc ACB:</u>

The length of the major arc ACB can be determined using the formula,

<u></u>m \widehat{ACB}=(\frac{\theta}{360})2 \pi r<u></u>

Substituting r = 3 and \theta=330, we get;

m \widehat{ACB}=(\frac{330}{360})2 \pi (3)

m \widehat{ACB}=\frac{1980}{360}\pi

m \widehat{ACB}=5.5 \pi

Thus, the length of the major arc ACB is 5.5π m

8 0
3 years ago
A car drives 50 miles east and then 40 miles due north. how long is the length of the diagonal
Bas_tet [7]
Diagonal = √50² + 40² = √2500+1600 = √3900 = 10√39 miles
4 0
3 years ago
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