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Evgesh-ka [11]
3 years ago
5

A nested decision structure can be used to test more than one condition. question 13 options:

Mathematics
1 answer:
enot [183]3 years ago
7 0
The answer for this question is A. True.

I hope that this helped!
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Emily spent a total of $38.04 on four CDs in a CD cost the same amount what is a reasonable amount for the cost of each city exp
pashok25 [27]
In order to find the cost of each CD, you would have to divide $38.04 by 4 CDs and you would get $9.51 as the cost of each CD. If you want to check if your answer is correct, you can either add $9.51 four times to get $38.04 or you can multiply $9.51 x 4 and you should get $38.04 remember that multiplication is always a way to check your answer for division problems and division is always a way to check an answer to your multiplicatiom problems. Just search it up for more info. Hope i helped! :)
7 0
3 years ago
The sum of a number times 9 and 30 is at least -28
Mars2501 [29]

Answer:

9n + 30 ≥ -28

Step-by-step explanation:

Let the number be n.  Then, symbolically, this statement is:

9n + 30 ≥ -28

8 0
3 years ago
Car dealerships claim to make most of their money from servicing cars. In a certain month, an Acura dealership sold fifteen less
MA_775_DIABLO [31]

Answer:

New cars sold = 20,

Used cars sold = 25

Cars serviced = 290

Step-by-step explanation:

In a month they sold fifteen less used cars than twice the number of new cars.

Lets say 'x' number of new cars were sold, then:

The number of used car sold is:

2\times x-15=2x-15

In the same month they serviced fifty more than twelve times the number of new cars sold. So the number of cars serviced is:

12\times x+50=12x+50

Altogether they sold or serviced 335 cars, so the sum of all the cars sold and serviced should be 335:

x+(2x-15)+(12x+15)=335

Solving for 'x' we get:

x+2x+12x-15+50=335

15x+35=335

15x=335-35=300

x=\frac{300}{15}=20

Therefore, the number of new cars sold in that month is 20.

Number of used car sold =2x-15=2\times 20-15=40-15=25

Number of cars serviced =12\times x+50=12\times20+50=240+50=290

We can also cross check by summing them up:

290+25+20=335

8 0
3 years ago
-2.5d ≥ 30 ??<br> i need help
just olya [345]

Answer:

I need more information, are we solving for D?

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the number of distinguishable permutations of the letters m, i, s, s, i, s, s, i, p, p, i.
Tatiana [17]

Solution:

we have been asked to find the number of distinguishable permutations of the letters m, i, s, s, i, s, s, i, p, p, i.

Here we can see

m appears 1 time.

i appears 4 times.

S appears 4 times.

p appears 2 times.

Total number of letters are 11.

we will divide the permutation of total number of letters by the permutation of the number of each kind of letters.

The number of distinguishable permutations=\frac{11!}{1!2!4!4!} \\

Hence the number of distinguishable permutations=\frac{11!}{1!2!4!4!}=34650 \\

4 0
3 years ago
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