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marta [7]
2 years ago
14

As an inventory manager, you must decide on the order quantity for an item. Its annual demand is 679 units. Ordering costs are $

7 each time an order is placed, and the holding cost is 10% of the unit cost. Your supplier provided the following price schedule. Quantity Price per Unit 1 - 100 $5.65 101 - 350 $4.95 351 or more $4.55 What ordering-quantity policy do you recommend
Mathematics
1 answer:
oee [108]2 years ago
8 0

The ordering-quantity that should be recommended will be 117 units.

<h3>How to calculate the order quantity?</h3>

The following can be deduced from the information given:

Demand = 679

Ordering cost = 7

Holding cost = 10%

Ordering quantity will be:

= ✓(2 × Demand × Ordering cost / Holding cost)

= ✓(2 × 679 × 7/0.1)

= ✓13580

= 116.53

= 117

Learn more about order quantity on:

brainly.com/question/27986709

#SPJ1

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Question
Arada [10]

Answer:

108

Step-by-step explanation:

if the width of the rectangle is 8, and the triangle is on the width of the rectangle, then the base of the rectangle is 8. the height is 7, so we use the formula area = height * base / 2 to find that the area of the triangular portion is 28. then, we find the area of the rectangle by doing 10 * 8(height * width) for a value of 80. the total area of the front of the house is 28 + 80: 108.

7 0
2 years ago
A. 60<br> B. 15<br> C. 120<br> D. 6
Montano1993 [528]

Answer:

C. 120

Step-by-step explanation:

The figure shows that angles BEC and KEC are congruent. Their measures are equal.

m<KEC = m<BEC

10x = 6x + 24

4x = 24

x = 6

m<BEK = 2m<KEC

m<BEK = 2 * 10x

m<BEK = 2 * (10)(6)

m<BEK = 2 * 60

m<BEK = 120

8 0
3 years ago
Please help! If the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms, what is the voltage?
Leona [35]

The value of the voltage is 18 - j volts if the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms option (c) is correct.

<h3>What is a complex number?</h3>

It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.

We have:

The current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms.

As we know,

V = IR

V = (3 + j2)(4 - j3)

\rm V=\left(3\cdot \:4-2\left(-3\right)\right)+\left(3\left(-3\right)+2\cdot \:4\right)j

j² = -1 (complex part)

After simplification:

V = 18 - j  volts

Thus, the value of the voltage is 18 - j volts if the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms option (c) is correct.

Learn more about the complex number here:

brainly.com/question/10251853

#SPJ1

6 0
2 years ago
If our galaxy were 1m wide, what would the distance to the Andromeda Galaxy be?
Setler79 [48]

Answer:

  • 25 m

Step-by-step explanation:

<u>The scale factor is </u>

  • 1 : 9.5×10²⁰ as we make our galaxy as small as 1 m.

<u>The distance to Andromeda would be:</u>

  • 2.4×10²² * 1/9.5×10²⁰ =
  • 2.4/9.5×10²²⁻²⁰ =
  • 0.25×10² =
  • 25 m
6 0
3 years ago
PLEASE HELP ASAP!!!!
Naily [24]

Answer:

2

Step-by-step explanation:

Using the rule of logarithms

log_{b} x = n ⇒ x = b^{n}

let

log_{2} 8 = n ⇒ 8 = 2^{n} , that is

2³ = 2^{n} ( equate exponents )

n = 3

and let

log_{3} ( \frac{1}{3} ) = n ⇒ \frac{1}{3} = 3^{n} , that is

3^{-1} = 3^{n} ( equate exponents )

n = - 1

then

log_{2} 8 + log_{3} (\frac{1}{3} )

= 3 + (- 1)

= 3 - 1

= 2

7 0
2 years ago
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