Question

triangle ABC is isosceles, angle B is vertex angle , AB = 20x -2, AC =25x, and BC =12 x +20. Find x and the length of each side of the triangle?

Answer 1

Length of AB = 18. 92

Length of AC = 26. 15

Length of BC = 32. 552

How to determine the sides of the triangle

Using the Pythagorean theorem, we have that

$(20 x-2)^2 = (12x + 20)^2 + (25x)^2$

Expand the bracket

$400x^2- 4 = 144x^2 + 400 + 625x^2$

Collect like terms

$400x^2 - 144x^2 - 625x^2 = 400 + 4$

$-369x^2 = 404$

Make x^2 subject

$x^2 = \frac{404}{369}$

$x = \sqrt{1.0948}$

$x = 1. 046$

Thus,

Length of AB = 20x -2 = 20(1. 046) - 2 = 18. 92

Length of AC = 25x = 25* 1.046 = 26. 15

Length of BC = 12x + 20 = 12(1. 046) + 20 = 32. 552

Learn more about isosceles triangles here:

brainly.com/question/1475130

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