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Oxana [17]
2 years ago
8

Please answer the question in the picture

Mathematics
1 answer:
rosijanka [135]2 years ago
3 0

answer:

(5x-1)(x-3)

explanation:

→ 5x² - 16x +3

→ 5x² -15x - x +3

→ 5x(x-3)-1(x-3)

→ (5x-1)(x-3)

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What's six tenths divided by seven <br><br><br><br><br><br><br><br>​
expeople1 [14]

Answer:

3/35

Step-by-step explanation:

7 0
3 years ago
Given g (c)=9 (c )^2+7=?
AVprozaik [17]
C^2+7 would equal 88. the first equation states that C=9, so you can just plug in 9 for C
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jok3333 [9.3K]
44-2*5=34
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7 0
2 years ago
-(y + 2) + 8 = 3<br> I’m so confused on this, please send help
Hoochie [10]

Don't be worried friend :)

-(y + 2) + 8 = 3

=> -(y + 2) = -5

=> y + 2 = 5

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7 0
3 years ago
Complete the square to rewrite y-x^2-6x+14 in vertex form. then state whether the vertex is a maximum or minimum and give its co
ycow [4]

Answer:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

Step-by-step explanation:

For this case we have the following equation given:

y= x^2 -6x +14

We can complete the square like this:

y= x^2 -6x +(\frac{6}{2})^2 +14 -(\frac{6}{2})^2

And solving we have:

y= x^2 -6x +9 + 14 -9

y= (x-3)^2 +5

And we can write the expression like this:

y-5 = (x-3)^2

The vertex for this case would be:

V= (3,5)

And the minimum for the function would be 3 and there is no maximum value for the function

4 0
3 years ago
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