If I'm understanding this correctly 20 rounded to the nearest ten would be 20
To find the 20th term in this sequence, we can simply keep on adding the common difference all the way until we get up to the 20th term.
The common difference is the number that we are adding or subtracting to reach the next term in the sequence.
Notice that the difference between 15 and 12 is 3.
In other words, 12 + 3 = 15.
That 3 that we are adding is our common difference.
So we know that our first term is 12.
Now we can continue the sequence.
12 ⇒ <em>1st term</em>
15 ⇒ <em>2nd term</em>
18 ⇒ <em>3rd term</em>
21 ⇒ <em>4th term</em>
24 ⇒ <em>5th term</em>
27 ⇒ <em>6th term</em>
30 ⇒ <em>7th term</em>
33 ⇒ <em>8th term</em>
36 ⇒ <em>9th term</em>
39 ⇒ <em>10th term</em>
42 ⇒ <em>11th term</em>
45 ⇒ <em>12th term</em>
48 ⇒ <em>13th term</em>
51 ⇒ <em>14th term</em>
54 ⇒ <em>15th term</em>
57 ⇒ <em>16th term</em>
60 ⇒ <em>17th term</em>
63 ⇒ <em>18th term</em>
66 ⇒ <em>19th term</em>
<u>69 ⇒ </u><u><em>20th term</em></u>
<u><em></em></u>
This means that the 20th term of this arithemtic sequence is 69.
Answer:
The cafeteria provides three meals per day.
<u>Reason 1</u>
Yes, they vary directly
As number of days increases ,Total number of meals i.e
1st day ⇒ 3
2nd day⇒6
3 rd day⇒9
4th day⇒12
......................
.........................
increases.
Total number of Meals = k×Number of days
But there is another possibility also
<u>Reason 2</u>
1 st day ⇒ 3
2nd day ⇒3
3rd day⇒ 3
.....................
.....................
As you can see from the above expression On each day number of meals is
constant.
So we can say that ,
On each Day=Constant amount of meal=3
So, there is no Proportionality between Days and Meal.
Lets x = missing angle
x = 180 - (60+80)
x = 180 - 140
x = 40
answer
40
