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Natali5045456 [20]
2 years ago
8

If the coordinates of the endpoints of a diameter of the circle are known, the equation of a circle can be

Mathematics
1 answer:
miskamm [114]2 years ago
6 0

The equation of the circle would be (x - 1)² + (y - 3)² = 65.

<h3>What is the equation of a circle?</h3>

The equation of a circle with center (h,k) and radius, r in center radius form is given;  

(x - h)² + (y - k)² = r²

The coordinates of the center of the circle can be calculated by the formula

((x₁ + x₂)/2, (y₁ + y₂)/2).

The point (x₁,y₁) = (9, 2) and (x₂,y₂) = (-7, 4).

So, ((9 -7)/2, (4 + 2)/2) = (1, 3).

Now, r² = (x₂ - x₁)² + (y₂ - y₁)².

Let (x₁, y₁) = (1, 3) and (x₂, y₂) = (-7, 4).

So, r² = (-7 -1)² + (4 - 3)²

= -8² + 1² = 64 + 1 = 65.

With center (h,k) = (1, 3) and r² = 65, we have

Thus, the equation would be (x - 1)² + (y - 3)² = 65.

Learn more about the equation of circle;

brainly.com/question/14786372

#SPJ1

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Answer:

Jessie scored higher than Reagan.

Step-by-step explanation:

We are given that Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 and standard deviation 100.

Jessie scored 30 on the ACT. The distribution of ACT scores in a reference population is normally distributed with mean 17 and standard deviation 5.

For finding who performed better on the standardized exams, we have to calculate the z-scores for both people.

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The z-score probability distribution for the normal distribution is given by;

                                    Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

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            \sigma = standard deviation = 100

Now, Reagan scored 1140 on the SAT, that is;

       z-score  =  \frac{1140-1000}{100}  =  1.4

2. <u>Finding z-score for Jessie;</u>

Let X = distribution of ACT scores

SO, X ~ Normal(\mu=17, \sigma^{2}=5^{2})

The z-score probability distribution for the normal distribution is given by;

                                    Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 17

            \sigma = standard deviation = 5

Now, Jessie scored 30 on the ACT, that is;

       z-score  =  \frac{30-17}{5}  =  2.6

This means that Jessie scored higher than Reagan because Jessie's standardized score was 2.6, which is 2.6 standard deviations above the mean and Reagan's standardized score was 1.4, which is 1.4 standard deviations above the mean.

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