C r = (n!)/(r!(n-r)!)
9 C 3 = (9!)/(3!*(9-3)!)
9 C 3 = (9!)/(3!*6!)
9 C 3 = (9*8*7*6!)/(3!*6!)
9 C 3 = (9*8*7)/(3!)
9 C 3 = (9*8*7)/(3*2*1)
9 C 3 = (504)/(6) 9 C 3 = 84
1. Slope-intercept form is y=mx+b, where m=slope and b=y-intercept. To answer this question, plug in the values they have given you.
y=mx+b
y=1/4x-5
2. To write an equation in slope-intercept form when given two points, use m=y2-y1/x2-x1
Remember: in an ordered pair, x comes first then y.
Plug the y- and x-values in. So, y2=6, y1=2 and x2=-2, x1=9
6-(-)2/-2-9= - 4/11.
The slope of your next equation would be m= - 4/11
Answer:
x= 6
Step-by-step explanation:
12+3x=30
3x+12=30
3x+12-12=30-12
3x=30-12
3x=18
3x divided by 3 = 18 divided by 3
x=18 over 3
18 divided by 3 is 6
x=6
The equation of the line is:
y-yo = m (x-xo)
Where,
m = (y2-y1) / (x2-x1)
Substituting values:
m = (8-4) / (6-2)
m = (4) / (4)
m = 1
Then, the equation is:
y-4 = 1 * (x-2)
Rewriting:
y = x-2 + 4
y = x + 2
The midpoint is:
k = ((x1 + x2) / 2, (y1 + y2) / 2)
k = ((2 + 6) / 2, (4 + 8) / 2)
k = ((8) / 2, (12) / 2)
k = (4, 6)
Then, the equation of the perpendicular line that passes through k is:
y = -x + b
Looking for b we have:
6 = -4 + b
b = 6 + 4
b = 10
Substituting:
y = -x + 10
Answer:
An equation of a line perpendicular to jl and passing through k is:
y = -x + 10
I think it’s C because inverses are basically the reciprocals of each other. These make 90 degree angles and the slopes product should be -1. C looks like the lines are perpendicular so I would go with that
