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2 years ago

A robot moves at a constant speed. The distance it moves and the time it spends moving are shown in this table:

Mathematics

1 answer:

Blababa [14]2 years ago

6 0

The equation to describe the relationship between t, the time, and d, the distance is t = 1.43d

<h3>What is a proportional relationship?</h3>

It is defined as the relationship between two variables when the first variable increases, the second variable also increases according to the constant factor.

As we know,

time(t) = speed(s)×distance(d)

Speed is constant:

t ∝ d

t = kd

k = t/d = 10/7 = 15/10.5 = 20/14 = 1.428 ≈ 1.43

The equation is:

t = 1.43d

Thus, the equation to describe the relationship between t, the time, and d, the distance is t = 1.43d

Learn more about the proportional here:

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What is 3/18 and 12/20 simplified

grin007 [14]

3/18= 1/6

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3 years ago

Read 2 more answers

Let R1 and R2 are the remainders when the polynomials x^3 + 2x^2 − 5ax − 7 and x^3 + ax^2 − 12x + 6 are divided by x + 1 and x −

Andru [333]

Answer:

2.44

Step-by-step explanation:

Given: x³ + 2x² - 5ax - 7 and x³ + ax² - 12x + 6

Also, R1 + R2 = 6

in order to find the value of a:

Let p(x) = x³ + 2x² - 5ax - 7 and q(x) = x³ + ax² - 12x + 6

Using remainder theorem i.e if a polynomial p(x) is divisible by polynomial of form x - a then remainder is given by p(a).

Then,

R1 = p( -1 ) = (-1)³ + 2(-1)² - 5a(-1) - 7 = -1 + 2 + 5a - 7 = 5a - 6

R2 = q( 2 ) = 2³ + a(2)² - 12(2) + 6 = 8 + 4a - 24 + 6 = 4a - 10

Now,

R1 + R2 = 6

5a - 6 + 4a - 10 = 6

9a = 22

a=2.44

Therefore, Value of a is 2.44

7 0

3 years ago

If 28% of students in College are near-sighted, the probability that in a randomly chosen group of 20 College students, exactly

cluponka [151]

Answer: (D) 16%

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_xp^x(1-p)^n-x$ , where n is the sample size , p is population proportion and P(x) is the probability of getting success in x trial.

Given : The proportion of students in College are near-sighted : p= 0.28

Sample size : n= 20

Then, the the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is given by :_

$P(x=4)=^{20}C_4(0.28)^4(1-0.28)^{20-4}\\\\=\dfrac{20!}{4!16!}(0.28)^4(0.72)^{16}\\\\=0.155326604912\approx0.16\%$

Hence, the probability that in a randomly chosen group of 20 College students, exactly 4 are near-sighted is closest to 16%.

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3 years ago

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horrorfan [7]

The number that should go in the box is 6.

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3 years ago

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