$(2x^2-3x+4) ( x^2+5x-7)= \\ \\=2x^2*x^2+2x^2*5x-2x^2*7-3x*x^2-3x*5x+3x*7+4*x^2+4*5x-4*7=\\ \\=2x^4+10x^3-14x^2 -3 x^3-15x^2+21x +4 x^2+20x-28=\\ \\=2x^4+7x^3-25x^2 +41x -28$

3 0

3 years ago

How to factorise x2 + 8x + 12

elena-s [515]

Answer:

I have made it in above figure

3 0

2 years ago

Read 2 more answers

Please help I need help with this badly asap !

evablogger [386]

Answer:

The third option

Step-by-step explanation:

It perfectly represents -24/3.

7 0

3 years ago

Divide 6 divided by 3/5 Answer only if u know please:)

meriva

Answer:

The answer is 10 or 10/1

3 0

3 years ago