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Sunny_sXe [5.5K]
2 years ago
11

Trinity has 12 ounces of tea leaves. If

Mathematics
2 answers:
Anettt [7]2 years ago
6 0

Answer:

4 cups of tea

Step-by-step explanation:

Given Trinity has 12 ounces of tea leaves, and 1 cup of tea requires 3 ounce of tea leaves,

No. of cups of tea = Total amount of tea leaves / Tea leaves required per cup of tea

= 12 / 3

= 4 cups of tea.

8_murik_8 [283]2 years ago
3 0

Answer:

4 cups of tea

Step-by-step explanation:

12 ounces ÷ 2/3 ounces = 18 cups of tea.

12/1 ÷ 2/3

12/1 x 3/2

= 36/2

=18

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Answer:

<em>(1,0) and (3,0)</em>

Step-by-step explanation:

The roots are always shown where the parabola crosses the x-axis.

In this particular graph, the parabola crosses at (1, 0) and (3, 0). Which means the roots are:

<em>x = 1 and x = 3</em>

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Assume that the average healthy body temperature is 98.249 degrees and the standard deviation is 0.733 degrees. How many standar
Leno4ka [110]

The standard deviation is 1.43 below the mean

<h3>How to determine the number of standard deviation?</h3>

The given parameters are:

Mean = 98.249

Standard deviation = 0.733

x = 97.2

To calculate the number of standard deviation below the mean, we use

x = \bar x - n\sigma

So, we have:

97.2 = 98.249 - n * 0.7333

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5 0
2 years ago
A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo
never [62]

Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

A previous study indicates that the proportion of left-handed golfers is 8%.

This means that \pi = 0.08

98% confidence level

So \alpha = 0.02, z is the value of Z that has a p-value of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.  

How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?

This is n for which M = 0.02. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 2.327\sqrt{\frac{0.08*0.92}{n}}

0.02\sqrt{n} = 2.327\sqrt{0.08*0.92}

\sqrt{n} = \frac{2.327\sqrt{0.08*0.92}}{0.02}

(\sqrt{n})^2 = (\frac{2.327\sqrt{0.08*0.92}}{0.02})^2

n = 996.3

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A sample of 997 is needed.

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