Answer:
AAS
Step-by-step explanation:
First, write down the given.
1. ∠V≅∠Y - Given
Since line WZ bisects ∠YWZ, which in other words splits it in half, that means that
2. ∠VWZ ≅ ∠YWZ - angle bisector
3. WZ ≅ ZW - reflexive property
Making the theorem AAS
R = { (x,y): 3x-y=0 }
The condition is 3x=y so that's not going to be any of these things.
R is reflexive if (x,x)∈R for all x. Let's check.
3x - y = 3x - x = 2x ≠ 0 necessarily. NOT REFLEXIVE
R is symmetric if (x,y)∈R → (y,x)∈R. Let's check.
(x,y)∈R so
3x-y = 0
y = 3x
Is (y,x)∈R. That would be true if 3y-x=0
3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC
R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R. Let's check.
3x-y = 0 so y=3x
3y-z = 0 so z=3y = 9x
3x - z = 3x - 9x = -6x ≠ 0 necessarily NOT TRANSITIVE
this would be your answer, <em>x = 1 - 15/2.</em>
Thanks,
<em>Deku ❤</em>
Answer:
10.6
10+ 2/3
Step-by-step explanation:
