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Natasha2012 [34]
2 years ago
10

What is the volume of a right circular cylinder with a radius of 6 m and a height of 9 m?

Mathematics
1 answer:
geniusboy [140]2 years ago
6 0

The volume of the right circular cylinder with a radius of 6 m and a height of 9 m is <u>1018 m²</u>.

The volume of a substance is the total space occupied by a three-dimensional object.

The volume of a right circular cylinder with a radius of r units and a height of h units is given by the formula <u>V = πr²h square units</u>.

We are asked to find the volume of the right circular cylinder with a radius of 6 m and a height of 9 m.

Substituting these values in the formula, we get Volume,

V = π(6)²(9) m² = 324π m² = 1017.876 m² ≈ 1018 m².

Therefore, the volume of the right circular cylinder with a radius of 6 m and a height of 9 m is <u>1018 m²</u>.

Learn more about volumes at

brainly.com/question/2965150

#SPJ10

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ExtremeBDS [4]

Answer:

95

Step-by-step explanation:

you first find out the angles mn and mt.

Since ns and ms are the same, we know ms is 35 degrees.

mt is 50, so we subtract 50 and 35 from 180, which is the degree of m.

so the answer is 95 degrees.

5 0
3 years ago
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Can someone pls help me . ASAPPP
STALIN [3.7K]

Volume without holes = 3 x 6 x 11 = 198 cubic inches.

Calculate volume of one hole:

3.14 x 0.5^2 x 3 = 2.355 cubic inches

There are 3 holes: 3 x 2.355 = 7.065

Subtract volume of the holes from the brick:

198 - 7.065 = 190.935 cubic inches.

Rounded to the nearest tenth: 190.9 cubic inches.

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2 years ago
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What are three even numbers that are less than 10 and have a sum of 18.<br> PLZ HELP MEH
Maksim231197 [3]
<u><em>8</em></u>, <em><u>6</u></em>, and <em><u>4</u></em>.
Eight plus six equals: 14
Then add four, and your get eighteen 
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3 0
3 years ago
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If you are adding two fractions that are both greater than 1/2, what must be true about the sum? Give three examples to support
slavikrds [6]

Answer:

The sum must be greater than 1

Step-by-step explanation:

Two fractions that are greater than 1/2 let's say

<u>Example 1</u>

3/4 and 7/8, the sum will be

3/4+7/8 with LCM of denominator as 8 sum=\frac {(3*2)+7}{8}=\frac {13}{8}=1\frac {5}{8} which is more than 1

<u>Example 2</u>

6/9 and 5/8 with the LCM of denominator as 72, the sum=\frac {(6*8)+(5*9)}{72}=\frac {93}{72}=1\frac {7}{24} which is greater than 1

<u>Example 3</u>

8/9 and 7/9 with the LCM of denominator as 9, the sum=\frac {8+7}{9}=\frac {15}{9}=1\frac {2}{3} which is greater than 1

3 0
3 years ago
You have been offered a project paying $300 at the beginning of each year for the next 20 years. what is the maximum amount of m
AfilCa [17]
This is a simple problem with some quick addition and subtraction, and a bit of multiplication.

First we figure out how much money you're spending in total, which is $300 each year, for 20 years, so 300 x 20 = 6,000. Now, since the problem is asking for a maximum amount for percentage rate, this means we find the 9% for all 20 years combined and not individually. 9% of 6,000 is of course 540, so if we subtract 540 from 6,000, we get 5,460.

This means your answer is $5,460
8 0
3 years ago
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