Lets be a price of the calculator - $ a
then , after using the coupon, you need to pay $(a-18)
and after using 15% discount , you need to pay (1-0.15)a=0.85a
then, if
(a-18) will be more than 0.85a, you should prefer 0.15 % discount, because it will be cheaper,
a-18> 0.85a
a-0.85a>18
0.15a > 18
a>120, that means that if the price of the calculator more than $120, 15% discount is better,
but if the price of the calculator is less than $120, you should choose $ 18 coupon.
for example, we have the price of the calculator $100
100-18=82,
100*0.85 =85, coupon is better.
If the price of the calculator $200
200-18=182,
200*0.85=170, so 15% discount is better
if price of the calculator is $120,
120-18=102
120*0.85=102,
it will not matter, what you are going to use, because you are going to pay the same amount of money
If they get unexpected results they could note what they could've done wrong or what they could change in a next trail of experiments. Or look back and see what different happened to they could've hypothesized. There could be many different courses on what to do next.
In other words, what is <em>y</em> if <em>x</em> is 0.
Look on the graph, a line passes through point, 
So we can conclude that at that very point the input <em>x</em> was 0 and the output <em>y</em> was -3 therefore,
Hope this helps.
<u>r3t40</u>
The equation is $130 + $31.67x = 500
Subtract 130 from both sides $31.67x = $370
Divide $31.67 from both sides
X=11.68
BUT
you can’t have .68 of a day so the answer is 11 days.
Answer:
The answer is D I believe
