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Katena32 [7]
2 years ago
11

Please answer with everything needed i appreciate everyones help

Mathematics
2 answers:
yawa3891 [41]2 years ago
4 0
Recheck the answer with your teacher.

nika2105 [10]2 years ago
3 0

Step-by-step explanation:

d = price of 1 drink

s = price of 1 sandwich

3d + 5s = 25.05

4d + 2s = 13.8

we can do this by combining both equations so that they is only one variable left.

e.g. multiply equation 1 by 4 and equation 2 by 3, and then subtract equation 2 from equation 1 :

12d + 20s = 100.2

- 12d + 6s = 41.4

------------------------------

0 14s = 58.8

s = 58.8/14 = $4.20

3d + 5s = 25.05

3d + 5×4.2 = 25.05

3d + 21 = 25.05

3d = 4.05

d = 4.05/3 = $1.35

so, each drink costs $1.35.

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It took an ice cream 28 minutes to drive through one neighborhood. The truck stopped driving through the neighborhood at 2:05 pm
VMariaS [17]

Answer:

Starting time: 1:37

Step-by-step explanation:

Instead of proof to solve the problem, let us prove that the starting time above is correct;

1. There are 60 minutes in an hour, so 60 - 37 = the minutes 'till 2:00, or 23 minutes

2. Knowing that the time the truck stopped driving through the neighborhood was 5 minutes past 2:00, the minute difference being 23 + 5, or <em>28 minutes</em>

<em>Proved: 28 minutes</em>

6 0
3 years ago
Adam is 9 years old and Billy is 11 years old. What will be the ratio of Adams’ age to Billy’s age in exactly one year’s time? G
son4ous [18]

Answer:

10 / 12

simplified:

5/6

since 5 is a prime number, we can't simplify this ratio any further

4 0
3 years ago
If 18is 45% of a value what is the value
DedPeter [7]
To solve this, create an equation that follows 45% of a value is 18. This would look like x*.45=18. Now, solve for x, x*.45=18, divide by .45, x=18/.45=40, making your value 40. To check, plug in your value to the equation 40*.45=18 and see if it stays true.
8 0
3 years ago
HELP PRECALC DO NOT UNDERSTAND WILL GIVE BRAINLIEST
Olegator [25]

Answer:

  the lower right matrix is the third correct choice

Step-by-step explanation:

Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).

Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.

__

We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.

The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...

  \left[\begin{array}{ccc|c}1&1&1&29000\\1+2&1-3&1-1&1000(29+1)\\0&0.15&0.15&2100\end{array}\right] =\left[\begin{array}{ccc|c}1&1&1&29000\\3&-2&0&30000\\0&0.15&0.15&2100\end{array}\right]

Already, we see that the second row matches that in the lower right matrix.

The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.

The correct choices here are the two you have selected, and <em>the lower right matrix</em>.

3 0
3 years ago
Use set-builder notation to describe the following sets: (a) {1,2,3,4,5,6,7} (b) {1, 10, 100, 1000, 10000} (c) {1,1/2, 1/3, 1/4,
Alja [10]

Answer:

A) The set builder notation is: {n | n∈Z, 1≤n≤7}.

B) The set builder notation is: \{10^x | x=0,1,2,3,4\}

C) The set builder notation is: \{\frac{1}{n} | n\in z\}

D) The set builder notation can be: \{x\ \in R | x=x^3\ and\ x\neq 1\}

Step-by-step explanation:

Consider the provided information,

We need to use set-builder notation to describe the following sets.

(a) {1,2,3,4,5,6,7}

Here, the number are integer starting from 1 to 7.

Thus, the set builder notation is: {n | n∈Z, 1≤n≤7}.

(b) {1, 10, 100, 1000, 10000}

The above set can be written as:

\{1, 10, 100, 1000, 10000\}=\{10^0, 10^1, 10^2, 10^3, 10^4\}

Thus, the set builder notation is: \{10^x | x=0,1,2,3,4\}

(c) {1, 1/2, 1/3, 1/4, 1/5, ...}

Here the numerator is 1 for each term but denominator is natural number.

Thus, the set builder notation is: \{\frac{1}{n} | n\in z\}

(d) {0}

The set builder notation can be: \{x\ \in R | x=x^3\ and\ x\neq 1\}

8 0
3 years ago
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