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1 year ago

Please answer with everything needed i appreciate everyones help

Mathematics

2 answers:

yawa3891 [41]1 year ago

4 0

Recheck the answer with your teacher.

nika2105 [10]1 year ago

3 0

Step-by-step explanation:

d = price of 1 drink

s = price of 1 sandwich

3d + 5s = 25.05

4d + 2s = 13.8

we can do this by combining both equations so that they is only one variable left.

e.g. multiply equation 1 by 4 and equation 2 by 3, and then subtract equation 2 from equation 1 :

12d + 20s = 100.2

- 12d + 6s = 41.4

------------------------------

0 14s = 58.8

s = 58.8/14 = $4.20

3d + 5s = 25.05

3d + 5×4.2 = 25.05

3d + 21 = 25.05

3d = 4.05

d = 4.05/3 = $1.35

so, each drink costs $1.35.

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Hannah was saving for a new snowboard. the one she wanted originally cost $ 109. it had been marked down 10% and then another 12

Semenov [28]

So marked down 10 then 12 so 10+12=22
mark down total is 22%
100-22=78
78% of 109=0.78 times 109=85.02
tax of 6%
6+100=106%

85.02 times 1.06=90.1212 or about 90.12
90<90.12
no she is short 12 cents

3 0

3 years ago

Read 2 more answers

Find Sin (BAC+30) 80POINTS

Ann [662]

Answer:

$\dfrac{2}{5}\sqrt{3}+\dfrac{3}{10}$

Step-by-step explanation:

Trigonometric Identities

$\sin (A \pm B)=\sin A \cos B \pm \cos A \sin B$

Trigonometric ratios

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

$\cos (\angle BAC)=\dfrac{12}{20}$

$\sin (\angle BAC)=\dfrac{16}{20}$

Angles

$\sin (30^{\circ})=\dfrac{1}{2}$

$\cos (30^{\circ})=\dfrac{\sqrt{3}}{2}$

Therefore, using the trig identities and ratios:

$\begin{aligned}\sin (\angle BAC + 30^{\circ}) & = \sin (\angle BAC) \cos (30^{\circ})+\cos (\angle BAC) \sin (30^{\circ})\\\\& = \dfrac{16}{20} \cdot \dfrac{\sqrt{3}}{2} + \dfrac{12}{20} \cdot \dfrac{1}{2}\\\\& = \dfrac{16}{40}\sqrt{3}+\dfrac{12}{40}\\\\& = \dfrac{2}{5}\sqrt{3}+\dfrac{3}{10}\end{aligned}$