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ratelena [41]
3 years ago
7

Paul is two years younger than Patricia. Daniel is 25% older than Patricia. Ten years ago, Daniel was 50% older than Patricia. H

ow old is Paul currently?
Mathematics
1 answer:
Step2247 [10]3 years ago
6 0
In this question, you can get 3 formula which was
1. Paul = Patricia - 2
2. Daniel = Patricia * 1.25
3. Daniel - 10 = (Patricia-10) * 1.5
    Daniel - 10 = 1.5 Patricia - 15
    Daniel= 1.5 Patricia -5

If you insert the 2nd equation into the 3rd, then you will get
1.25 Patricia = 1.5 Patricia -5
0.25 Patricia = 5
Patricia = 20

Then insert the result into 1st equation
Paul = Patricia - 2= 20-2= 18 years
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The scatter plot shows a scuba diver's depth in the ocean. The equation of the trend link shown is y = -3.29x - 10. Predict what
TiliK225 [7]

<u>It's not given a scatter plot not the characteristics of the variables, but it can be safely assumed as shown below</u>

Answer:

<em>The diver's depth will be -42.9 after 30 minutes</em>

Step-by-step explanation:

The equation of the trend (or best fit line) for the scuba diver's depth in the ocean is:

y = -3.29x - 10

Where y is the diver's depth and x is the time in minutes.

To predict the diver's depth at x=30 minutes, substitute in the equation:

y = -3.29(10) - 10

y = -32.9 - 10

y = -42.9

Since no units are provided for y, the answer is:

The diver's depth will be -42.9 after 30 minutes

6 0
3 years ago
What’s the midpoint P(0,-2), Q(1,1
LiRa [457]

You would have to add x1 + x2 and divide by 2. do the same with y1 and y2.

(1/2,-1/2)

6 0
3 years ago
From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.
zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}

, where \overline{x} = sample mean.

z*= critical z-value

n= sample size.

\sigma = Population standard deviation.

By considering the given question , we have

\overline{x}= 21.69

\sigma=3.23

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}

=21.69\pm (1.96)\dfrac{1.7}{7.61577}

=21.69\pm (1.96)(0.223221)

\approx21.69\pm0.83

=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

7 0
3 years ago
Is 1/2 between 0.1 and 0.2?
Nady [450]
No, 1/2=0.5


This is because half of one is 0.5, since 0.5 x 2 = 1.

0.1 written as a fraction would be 1/10, since 0.1 x 10 = 1.
0.2 written as a fraction would be 1/5, since 0.2 x 5 = 2
3 0
3 years ago
You reflect the point ( -7, -6) across
Leokris [45]
Reflecting is pushing it across from one side to another.
The answer would be (7,6)
Sorry I'm late.
4 0
4 years ago
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