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RSB [31]
2 years ago
15

In the diagram, line I and line m are parallel lines cut by transversal n. b a n m

Mathematics
1 answer:
baherus [9]2 years ago
4 0

The measure of both the interior angles are 70 and 110 degree.

<h3>What are Parallel Lines ?</h3>

Lines they never intersect with each other and the distance between them always remains same are called parallel lines.

It is given that

Line l and m are parallel lines and are intersected by a transversal ,n

Interior angles of the same side are (2x−8) degree and (3x−7) degree

Applying the property of interior angles of parallel lines

2x -8 + 3x - 7 = 180 degree

5x -15 = 180

5x = 195

x = 39 degree

Both the angles have measure of

2 * 39 - 8 = 70 degree

3 * 39 -7 = 110 degree

Therefore the measure of both the angles are 70 and 110 degree.

The complete question is

Two parallel lines l and m are cut by a transversal  n . If the interior angles of the same side of n are (2x−8) degree and (3x−7) degree  , find the measure of each of these angles.

To know more about Parallel Lines

brainly.com/question/16701300

#SPJ1

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Find the missing numerator in each of the following fractiions? A. 5/6= /12. B. 2/4= /36. C. 2/5=/20. D. 4/25=/100
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<u>Answer:</u>

A. 10

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C. 8

D. 16

<u>Step-by-step explanation:</u>

We are given a number of incomplete fractions and we are to find the missing numerator in each one of these.

To find the missing numerator or denominator, we multiply the numerator and the denominator by the same number to get an equivalent fraction.

A. \frac{5}{6} =\frac{10}{12}

Here the denominator is multiplied by 2 so the denominator will also be multiplied by 2 to get 10.

B. \frac{2}{4} =\frac{18}{36}

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4 years ago
70 POINTS!
siniylev [52]
You can solve this question with pythagorean theorem > {a}^{2} + {b}^{2} = c^{2}

Based on the information, you already have one side (a or b, doesn't matter, 12) and the hypotenuse (the cut, c, 15)

So: 
1. 12^{2} + b^{2} = 15^{2}
2. 144+b^{2} = 225
3. b^{2} = 225 - 144 = 81
4. b=  \sqrt{81}
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That’s the answer for this problem

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