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2 years ago

The point stope form of the equation of the line that passes through (-4,-3) and (12, 1) is y-1 = (x-12). What is

Mathematics

1 answer:

zalisa [80]2 years ago

3 0

Answer:

x-4y = 8

Step-by-step explanation:

The standard form for the equation of a line is Ax+By=C where A is a positive integer and B and C are integers

First we need to find the slope

m = ( y2-y1)/(x2-x1)

m = (-3-1) / (-4-12)

=-4/-16

= 1/4

The point slope form is

y-1 = 1/4(x-12)

Multiply each side by 4

4(y-1 )= 4*1/4(x-12)

4(y-1) = x-12

4y -4 = x-12

Subtract 4y from each side

4y-4-4y = x-4y -12

-4 = x-4y -12

Add 12 to each side

-4+12 = x-4y -12+12

8 = x-4y

x-4y = 8

The standard form is x-4y = 8

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What's 1.3 repeating as a fraction

Bogdan [553]

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To find this:

x = 1.3333333333333...

Multiply by 10:

10x = 13.3333333333...

Subtract x = 1.3333333333333333....:

9x = 12.

Divide by 9:

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3 years ago

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3 years ago

Out of six computer chips, two are defective. If two chips are randomly chosen for testing (without replacement), compute the pr

Ratling [72]

Answer:

The probability that of the two chips selected both are defective is 0.1089.

Step-by-step explanation:

Let X = number of defective chips.

It is provided that there are 2 defective chips among 6 chips.

The probability of selecting a defective chip is:

$P(X)=p=\frac{2}{6}=0.33$

A sample of n = 2 chips are selected.

The random variable X follows a Binomial distribution with parameter n = 2 and p = 0.33.

The probability function of a Binomial distribution is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0, 1, 2, ...$

Compute the probability that of the two chips selected both are defective as follows:

$P(X=2)={2\choose 2}(0.33)^{2}(1-0.33)^{2-2}=1\times 0.1089\times 1=0.1089$

Thus, the probability that of the two chips selected both are defective is 0.1089.

The sample space of selecting two chips is:

S = (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5)

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3 years ago

Find the inverse of each of the given functions. f(x) = 4x − 12

frez [133]

Answer: $f^{-1}(x)=\frac{x+12}{4}$

Step-by-step explanation:

Let f(y)=x

$x=4y-12\\\\x+12=4y\\\\y=\frac{x+12}{4}\\\\f^{-1}(x)=\frac{x+12}{4}$

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