Answer:
6 minetes? how does this work?
Step-by-step explanation:
Answer:
-3 - - 6 = 3
2 - - 8 = 10
Step-by-step explanation:
You use keep change change. When subtracting negative you get the first number change the sign to the opposite, then change the second numbers sign
<h2>example
- -3 - - 6</h2><h2> -3 + 6</h2><h2> 2 - - 8</h2><h2> 2 + 8</h2>
Answer:
Option B is right
Step-by-step explanation:
We have in a triangle there are some properties inherent.
One is the perpendicular bisectors of all sides are concurrent.
These three concur at a point called the circumcentre of the triangle.
When we draw perpendicular bisector for a side AB, we get that all points on the perpendicular bisector are equidistance from A and B.
When we take the point of intersection of perpendicular bisector of AB and BC, we have the intersecting point S(say) is equidistant from A and B and also from B and C
In short this is equidistant from all 3 vertices and hence is centre of circumcicle of triangle ABC
Answer:
Step-by-step explanation:
This is good! The length of the metal is 20 inches longer than the width. But we fold up 4-inch flaps on each side, so the height of the box is 4 inches, and the length and width will each decrease by 8 inches (4 inches on each side). Since the length and width decrease by the same amount, the length will still be 20 inches longer than the width. So the equations would be:
l = w + 20
vol = l x w x h = 1716 in3
1716 = (w + 20)(w)(4)
1716 = 4w2 + 80w
4w2 + 80w - 1716 = 0
4(w2 + 20w - 429) = 0
4(w + 33)(w - 13) = 0
w + 33 = 0, so w = -33
w - 13 = 0, so w = 13
Since the width can't be negative, the width of the box is 13 and the length is 33 (13 + 20).
But remember, the length and width of the piece of metal are each 8 inches longer than the box, so it was 41 inches by 21 inches.
Y= (2x-20)/ 5 then you replace y so with a simple calculation u get x than u replace x with it value to get y as simple as that
