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lozanna [386]
2 years ago
9

BRAINLIEST!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Marat540 [252]2 years ago
8 0

Answer:

The Slope: 0

The y-intercept: (0,0_

x y

0 0

1 0 (there is supposed to be a line between the x and y that goes down all the way down the numbers but i cannot type that)

Step-by-step explanation:

loris [4]2 years ago
4 0

Answer:

Move all the points on the graph two points to the right

Step-by-step explanation:

f(x-2) is just a translation to the right by 2. The whole formula is typically y = a f(b(x + c)) + d. In this case, the C value is the one being changed and that indicates a translation left or right. -2 indicates 2 to the right.

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Which division sentence is represented by the model?
amid [387]

Answer:

19÷9=23

Step-by-step explanation:

correct me if I'm wrong

6 0
2 years ago
Me again.. can someone please help me with this? It's trigonometry, and I'm not very good at it...
hodyreva [135]
Check the picture below.

8 0
4 years ago
28-9X=-12-11X<br><br> How would you answer that?
jolli1 [7]
28-9x=-12-11x \\\\ -9x+11x=-12-28 \\\\ 2x=-40 \\\\ \boxed{x=-\frac{40}{2}=-20}
4 0
3 years ago
Please help me do this
alekssr [168]

Answer:

0.39789 ft

Step-by-step explanation:

2πR = 2.5

R=2.5/2π

Hope this helps!

Please like If it does

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6 0
3 years ago
Math help Please!!!!
GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation  −2y=3x+7 in the form y=-\dfrac{3}{2}x-\dfrac{7}{2}. Here the slope of the given line is  m_1=-\dfrac{3}{2}. If m_2 is the slope of perpendicular line, then

m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.

Answer 1: \dfrac{2}{3}

Part B. The slope of the line y=−2x+3 is -2. Since -\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2, then lines from part A are not parallel to line a.

Since -2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1, both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line y=\dfrac{x}{4}+5 is \dfrac{1}{4}. Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then

7=-4·2+b,

b=7+8,

b=15.

Answer 4: y=-4x+15.

Part E. Consider vectors \vec{p}_1=(-c-0,0-(-d))=(-c,d)\quad \text{and}\quad \vec{p}_2=(0-b,a-0)=(-b,a). These vectors are collinear, then

\dfrac{-c}{-b}=\dfrac{d}{a},\quad \text{or}\quad -\dfrac{a}{b}=-\dfrac{d}{c}.

Answer 5: -\dfrac{a}{b}=-\dfrac{d}{c}.

5 0
4 years ago
Read 2 more answers
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