Answer:
The distance between two points is √169 or 13.
Step-by-step explanation:
In the question we need to find the distance between two points 5,6 and 0,-6 given.
Distance between two points can be found using the formula:

Putting the given points in the formula we get,
x₂ = 0, x₁ = 5, y₂= -6, y₁= 6

So, the distance between two points is √169 or 13.
Answer:
22.5 degrees
Step-by-step explanation:
90 = x + 3x
90 = 4x (divide by 4)
22.5 = x
22.5 + 67.5 = 90
Answer:the weight after 225 days is
22885 kilograms
Step-by-step explanation:
The initial weight of the blue whale calf at birth is 2725 kilograms. blue whale calf gains 90 kilograms of weight each day for the first 240 days after its birth. The weight increases in arithmetic progression. This means that the first term of the sequence, a is 2725, the common difference, d is 90.
The formula for the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
n is the number of terms of the sequence.
a is the first term
d is the common difference
We want to determine its weight, T225 after 225 days after it’s birth. It means that n = 225
Therefore
T225 = 2725 + (225 - 1)90
T225 = 2725 + 224×90 = 2725 + 20160
T225 = 22885
Answer:
55 inches
Step-by-step explanation:
2 posters x 28 inches each = 56
221 - 56 = 165 inches
3 blank spaces on wall
165 ÷ 3 = 55 inches between posters and on either side