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Alex Ar [27]
1 year ago
9

A line has slope Four-thirds. Through which two points could this line pass?

Mathematics
1 answer:
lisabon 2012 [21]1 year ago
6 0

Answer:

Two points this line can pass through <em>(1, 4/3) and (2, 8/3)</em>

Step-by-step explanation:

The equation of the line is written in the slope-intercept form,

y = mx + b

where m represents the slope

          b represents the y-intercept

where the format of a point is (x, y)

<u>Given:</u>

  • slope = 4 / 3
  • equation: y = 4/3x

we can plug in a number for x to find y

<u>when x = 0,</u>

y = 4/3(0)

y = 0

<em>point: (0,0)</em>

<u>when x = 1,</u>

y = 4/3(1)

y = 4/3

<em>point: (1, 4/3)</em>

when x = 2,

y = 4/3(2)

y = 8/3

<em>point: (2, 8/3)</em>

Learn more about slope and y-intercept here: brainly.com/question/12763756

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AleksandrR [38]

The four angles of a quadrilateral are  30°, 60°, 150°, and 120°  if the four vertices of an inscribed quadrilateral divide a circle in the ratio 1:2:5:4.

<h3>What is quadrilateral?</h3>

It is defined as the four-sided polygon in geometry having four edges and four corners.

We have the four vertices of an inscribed quadrilateral divide a circle in the ratio:

1:2:5:4

Let the sides of the quadrilateral be x, 2x, 5x, 4x.

We know the sum of all angles of quadrilateral = 360°

x+2x+5x+4x=360

12x = 360

First angle, x = 30°

Seconds angle, 2x = 2×30 ⇒ 60°

Third angle, 5x = 5×30 ⇒ 150°

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Thus, the four angles of a quadrilateral are  30°, 60°, 150°, and 120°

Learn more about the quadrilateral here:

brainly.com/question/6321910

3 0
2 years ago
Please help i dont understand thank you
Alenkasestr [34]

Answer:

Part a)

We need to find the equation of a straight line passing through two given points in slope-intercept form

Part b)

The information given; we are given two points where the line passes through; (0, -4) and (-2, 2)

Part c)

We shall first determine the slope of the line using the formula;

change in y/change in x. Next, we determine the value of the y-intercept using the general form of the equation of a straight line in slope-intercept form; y = mx+c

Part d)

The slope of the line is calculated as;

(2--4)/(-2-0) =6/-2 = -3

The equation of the line in slope-intercept form becomes;

y = -3x +c

We use the point (0, -4) to determine the value of c;

-4 = -3(0)+c

c = -4

Part e)

Final solution thus becomes;

y=-3x-4

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3 years ago
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Answer:

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