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3 years ago

Determine the center and radius of the following circle equation:

Mathematics

1 answer:

ioda3 years ago

5 0

Answer:

C(5,-9) and r=8.

Step-by-step explanation:

C(p, q) - center

r=radius

k:x^2 +y^2 +dx+ey+f=0

x^2+y^2 - 10x+18y+42=0

d=-10, e=18, f=42

p=-d/2=-(-10)/2=10/2=5

q=-e/2=-18/2=-9

r^2 =p^2+q^2-f

r^2 =5^2 +(-9)^2 - 42

r^2=25+81-42

r^2 =106-42

r^2 =64

r=sqrt(64)

r=8

C(p,q)=C(5,-9) r=8

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3 years ago

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3 years ago

Find the length of diagonal HJ. Round to the nearest hundredth.

Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ , where

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

∵ The coordinates of point J are (5 , -3)

∴ $x_{1}=-4$ and $x_{2}=5$

∴ $y_{1}=3$ and $y_{2}=-3$

- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = $\sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}$

∴ HJ = $\sqrt{(9)^{2}+36}=\sqrt{81+36}=\sqrt{117}=10.81665$

∴ HJ = 10.82

* The length of the diagonal HJ is 10.82 units

7 0

2 years ago

How do you solve -28-6x=-2(1-3x)-2

Zina [86]

-28-6x=-2(1-3x)-2

-28-6x=-2+6x-2

-28-6x=-4+6x

-6x-6x=-4+28

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6 0

2 years ago

Read 2 more answers

ANSWER ASAP ILL MARK BRAINLIEST!!!!

Korolek [52]

Answer:

$2 {x}^{2} - 6x - 1 = 0 \\ a = 2 \: \: \: b = - 6 \: \: \: c = - 1 \\ \\ x = \frac{6\binom{ + }{ - } \ \sqrt{ {6}^{2} - 4(2)( - 1)} }{2 \times 2} \\ \\ x = \frac{6 \binom{ + }{ - } \sqrt{44} }{4} \\ x = \frac{6 + \sqrt{44} }{4} \\ \\ or x = \frac{6 - \sqrt{44} }{4}$

I hope that is useful for you :)

8 0

2 years ago