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2 years ago

How to tell if something is a function.

Mathematics

1 answer:

insens350 [35]2 years ago

5 0

Answer:

it is when it can make a mathematical statement

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Need help with this homework question

blondinia [14]

The question is not attach!

3 0

2 years ago

HURRY AND AWNSER SISSYS

Llana [10]

Answer:

Neither

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Felicia invested $25,000 into an account earning 3% interest compounded annually. She makes no other deposits into the account a

madam [21]

The formula is
A=p (1+r)^t
A future value?
P present value 25000
R interest rate 0.03
T time 9 years

A=25,000×(1+0.03)^(9)
A=32,619.33

7 0

3 years ago

Horatio is solving the equation -3/4+2/5x=7/20x-1/2. Which equations represent possible ways to begin solving for x? Check all t

trapecia [35]

Answer:

2/5x=7/20x+1/4
-3/4=-1/20x-1/2
-3/4+1/20x=-1/2

Step-by-step explanation:

If you add 3/4 to both sides of the equation, you get ...

... 2/5x = 7/20x + 1/4 . . . . first choice

If you subtract 2/5x from both sides of the equation, you get ...

... -3/4 = -1/20x -1/2 . . . . third choice

If you subtract 7/20x from both sides of the equation, you get ...

... -3/4 +1/20x = -1/2 . . . . last choice

Choices 2 and 4 are erroneous versions of choices 1 and 3, so do not apply.

4 0

3 years ago

Read 2 more answers

Solve the equation x. If a solution is extraneous, be sure to identify it in your final answer.

Igoryamba

Answer:

x=2 is the only solution

Step-by-step explanation:

The given expression is;

$\sqrt{x+7}-1=x$

Add 1 to both sides of the equation;

$\sqrt{x+7}=x+1$

Square both sides ;

$(\sqrt{x+7})^2=(x+1)^2$

$x+7=x^2+2x+1$

This implies that;

$x^2+2x-x+1-7=0$

$x^2+x-6=0$

Split the middle term

$x^2+3x-2x-6=0$

$x(x+3)-2(x+3)=0$

$(x+3)(x-2)=0$

x=-3,or x=2

Check for extraneous solutions by substituting into the original equation.

When x=-3,

$\sqrt{-3+7}-1=-3$

$\sqrt{4}-1\ne-2$

This is an extraneous solution.

When x=2,

$\sqrt{2+7}-1=2$

$\sqrt{9}-1=2$

$3-1=2$ . This is true

This is not an extraneous solution

6 0

3 years ago