Answer:
The outside temperature is -45.8°C
Explanation:
When a gas keeps on constant its moles and its pressure, we can assume that volume will be increased or decreased as the T° (absolute T° in K).
V1 / T1 = V2 / T2
2.95L/298K = 2.25L / T2
(2.95L/298K ) . T2 = 2.25L
T2 = 2.25L . 298K / 2.95L
T2 = 227.2K
T°K - 273 = T°C
227.2K - 273 = -45.8°C
The answer is D because for light 3 to function switch d does not have to turn on
According to Gases law, we know,
PV/T = Constant
So, P₁V₁/T₁ = P₂V₂/T₂
Here, P₁ = 108 kPa
V₁ = 592.2 mL
T₁ = 10+273 = 283 K
P₂ = ?
V₂ = 750 mL
T₂ = 28.9+273 = 301.9
Substitute their values,
108 * 592.2 / 283 = P₂ * 750 / 301.9
P₂ = 63957.6 * 301.9 / 283 * 750
P₂ = 19308799.44 / 212250
P₂ = 90.97 kPa
In short, Your Final Answer would be: 90.97 kPa
Hope this helps!
Answer:
5. The valence electrons of both fluorine and carbon are found at about the same distance from their respective nuclei but the greater positive charge of the fluorine nucleus attracts its valence electrons more strongly.
Explanation:
Both fluorine and carbon are located in the second period of the periodic table, it means that they have 2 shells, so the valence electrons are found at about the same distance from their respective nuclei.
But fluorine has a higher atomic number, 9, than the carbon, 6. The atomic number represents how many protons there are in the nucleus, then there are more protons (positive charge) at the fluorine nucleus, and because of that, the attraction force between the nucleus and the valence electron is stronger in fluorine.
If the force is stronger, it will be necessary more energy to break the bond, so it will be harder to remove an electron from fluorine than from carbon.
(a) sodium hydroxide + ammonium sulfate --> sodium sulfate + ammonium hydroxide
sodium sulfate precipitates in aqueous solutions
(b)<span> niobium(V) sulfate + barium nitrate → Barium sulfate + niobium nitride
both do not precipitate in aqueous solution
</span>(c) strontium bromide + silver nitrate ---> strontium nitrate + silver bromide
both do not precipitate in aqueous solution
