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aleksandr82 [10.1K]
3 years ago
7

If x = 5 and y = 7, will statement if(x!=y) execute? A. yes B. no

Computers and Technology
1 answer:
Phoenix [80]3 years ago
7 0
A. yes

!= means not equal, so if you substitute, you get if(5 is not equal to 7), which renders True and executes
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from random import randint

answers = ["Scissors", "Rock", "Paper"]

computer = answers[randint(0, 2)]

continue_loop = False

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   player_choice = input("Choose a number, 0 = Scissors, 1 = Rock , 2 = Paper?")

   player_choice = answers[int(player_choice)]

   if player_choice == computer:

       print("Tie!")

   elif player_choice == "Rock":

       if computer == "Paper":

           print("You lose!", computer, "covers", player_choice)

       else:

           print("You win!", player_choice, "smashes", computer)

   elif player_choice == "Paper":

       if computer == "Scissors":

           print("You lose!", computer, "cut", player_choice)

       else:

           print("You win!", player_choice, "covers", computer)

   elif player_choice == "Scissors":

       if computer == "Rock":

           print("You lose...", computer, "smashes", player_choice)

       else:

           print("You win!", player_choice, "cut", computer)

   else:

       print("That's not a valid play. Check your spelling!")

   continue_or_not = input("Would you like to play again? Y/N")

   continue_or_not = continue_or_not.lower()

   if continue_or_not != "y":

       break

   computer = answers[randint(0, 2)]

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