What is the y-intercept of this quadratic function f(I)=-i2+10i-22

Mathematics

1 answer:

const2013 [10]1 year ago

4 0

The y-intercept of the quadratic equation is -47.

<h3>What is Quadratic Equation?</h3>

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.

Here, given quadratic equation;

f(i) = i² + 10i - 22

or, y = i² + 10i - 22

y = i² + 2.5x - (47-25)

y = i² + 2.5x + 25 - 47

y = (i+5)² - 47

Thus, the y-intercept of the quadratic equation is -47.

Learn more about Quadratic Equations from:

brainly.com/question/2263981

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Rectangle KLMN is graphed on the coordinate plane below. On a coordinate plane, rectangle K L M N has points (2, negative 2), (5

gladu [14]

Answer: The correct option is (A) (2, -2).

Step-by-step explanation: Given that rectangle with vertices at K, L, M and N is graphed on the coordinate plane as shown in the figure.The figure is rotated 360° counterclockwise using the origin as the center of rotation.

We are to find the location of the image of point K after the rotation.

We know that

a rotation of 360° in counterclockwise direction about the origin map a point to itself. That is, the co-ordinates of the image point will be same as the original one.

From the figure, we see that the co-ordinates of point K are (2, -2).

Therefore, after rotation of 360° counterclockwise using the origin as the center of rotation,

the co-ordinates of the image of point K will also be (2, -2).

Thus, the location of the image of point K is (2, -2).

Option (A) is CORRECT.

8 0

2 years ago

BRAINLY FOR THE FASTEST WITH GOOD EXPLANATIONS

Neporo4naja [7]

So, when we're tasked with things like this, rewriting everything in terms of sine and cosine and combining fractions often trivializes things, so doing just that gives us:

$\frac{\frac{1}{\cos{x}}-\frac{1}{\sin{x}}}{\frac{\cos{x}}{\sin{x}}-1}= \\\frac{\frac{=(\cos{x}-\sin{x})}{\cos{x}\sin{x}}}{\frac{\cos{x}}{\sin{x}}-\frac{\sin{x}}{\sin{x}}}=\\\frac{-(\cos{x}-\sin{x})}{\cos{x}\sin{x}}*\frac{\sin{x}}{\cos{x}-\sin{x}}=\\-\frac{1}{\cos{x}}$