The end behaviour of a graph is defined as what is going on at the end of each graph as the function approaches positive or negative infinity the leading term determines what the graph looks like as a move towards infinity
Use our brains and what we know
f(x)=a(x-h)²+k
vetex is (h,k)
and a is te leading coefient
if directix is below the focus, then it opens up and a is positive
if directix is above focus, then it opens down and a is negaitve
vertex is in between directix and focus
so
(3,-1) and y=1
-1<1
so directix is above
a is negative
directly in between
distance from -1 to 1 is 2
2/2=1
1 above (3,-1) is (3,0)
vertex is (3,0)
y=a(x-3)²+0
y=a(x-3)²
the only option with a negative 'a' value is B
answer is B
Find x and y intercept and plot
set x to zero and find y
set y to zero and find x
tada, 2 points
if x=0, then y=-4
if y=0, then x=-16
we havee the points
(0,-4) and (-16,0)
or
y=-1/4x-4
Answer: Yes
Step-by-step explanation:
7+(5)=12
(9)+3=12
