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Tcecarenko [31]
2 years ago
5

In how many ways can four people with different heights line up single-file so that exactly two people are taller than the perso

n behind them?
Mathematics
1 answer:
yanalaym [24]2 years ago
6 0

The number of ways by which exactly 2 people are taller than the person behind them is; 6.

<h3>What number of ways can they line so that exactly two people are taller than the person behind them?</h3>

It follows from content that since 4 individuals with different heights are to line up, the 2 individuals who must be taller than the person behind them are represented as one entity and must be in the 1st and 2nd position or the 2nd and 3rd position.

Hence, the number of ways is; 6 upon counting the number of possible outcomes.

Read more on arrangement;

brainly.com/question/1427391

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2x + 1=4x-3 solve for x
loris [4]

Answer:

x = 2

Step-by-step explanation:

To start, you want to isolate x.

To do so, get all the x terms to one side.

2x + 1 = 4x - 3

Subtract -4x on both sides.

-2x + 1 = -3

Then, subtract 1 on both sides.

-2x = -4

Finally, divide -2 on both sides.

x = 2

3 0
3 years ago
What are the values of x and y
sertanlavr [38]

Answer:add then divide

Step-by-step explanation:

5 0
3 years ago
Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
Which relations are functions?
guapka [62]

Answer:

The 1st and 2nd graph are functions while the 3rd and 4th aren't.

Step-by-step explanation:

The first and second graph doesn't have more than one output for each input. The third and fourth graph isn't a function since there's more than one output for the same input given. If you do the vertical line test, then you'll know which one is a function and which one is not a function. Hope this helps :)

3 0
3 years ago
4x^2+19x+19=0 to the nearest tenth
zzz [600]

Answer:

the answer is

Step-by-step explanation:

7 0
3 years ago
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