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dexar [7]
1 year ago
5

Easy! 40 PTS!!! Log Functions

Mathematics
1 answer:
Umnica [9.8K]1 year ago
4 0

Answer:

C

Step-by-step explanation:

When x is negative    1/2 ^x  becomes   1 / ( 1/2 ^x)   meaning it is quite large as x becomes more negative

   when x = 0  the value is 1  

  as x increases from 0 to + inf   the value becomes smaller...but never negative

   the only graph that fits is C

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21/100 simplified

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Rewrite the equation below so that it does not have fractions.
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Step-by-step explanation:

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2 years ago
Set up but do not solve for the appropriate particular solution yp for the differential equation y′′+4y=5xcos(2x) using the Meth
taurus [48]

Answer:

So, solution of  the differential equation is

y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

Step-by-step explanation:

We have the given differential equation: y′′+4y=5xcos(2x)

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y''+4y=0\\\\r^2+4=0\\\\r=\pm2i\\\\

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y_h(t)=c_1e^{-2i t}+c_2e^{2i t}

Now, we finding a particular solution.

y_p(t)=A5x\cos 2x\\\\y'_p(t)=A5\cos 2x-A10x\sin 2x\\\\y''_p(t)=-A20\sin 2x-A20x\cos 2x\\\\\\\implies y''+4y=5x\cos 2x\\\\-A20\sin 2x-A20x\cos 2x+4\cdot A5x\cos 2x=5x\cos 2x\\\\-A20\sin 2x=5x\cos 2x\\\\A=-\frac{x}{4} \cot 2x\\

we get

y_p(t)=A5\cos 2x\\\\y_p(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x\\\\\\y(t)=y_p(t)+y_h(t)\\\\y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

So, solution of  the differential equation is

y(t)=-\frac{5x^2}{4}\cot 2x\cdot \cos  2x+c_1e^{-2it}+c_2e^{2it}\\

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3 years ago
There is a bag with only red marbles and blue marbles.
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49 red marbles

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We should first make 5/12 have a base of 84, so that'll be

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DUBS

Please consider giving me a brainliest! Thank you.

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3. What is the hypothesis of the following conditional statement?
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A: Two angles form a right angle.

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