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gtnhenbr [62]
1 year ago
10

(15-10)-(14+12+ (8+5)​

Mathematics
2 answers:
Travka [436]1 year ago
6 0

Answer:

-34

Step-by-step explanation:

Remove all brackets by multiplying the existing math signs then take it from there

nata0808 [166]1 year ago
5 0

(15-10)-(14+12+ (8+5)​

5 - (14 + 12 + (8 + 5)

5 - (14 + 12 + 13)

5 - 39

-34

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When written in standard form, the product of (3+x) and (2x-5)
Mariulka [41]

Answer:

2x^2+x-15

Step-by-step explanation:

6x-15+2x^2-5x

2x^2+x-15

5 0
2 years ago
Stacy exercises 3 days each week by walking around the soccer field near her home the field is 80 yards wide and 115 yards long
zhenek [66]

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3 years ago
Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

4 0
2 years ago
A restaurant needs to build a wheelchair ramp for its customers. The angle 2 of elevation for a ramp is recommended to be 5 degr
melomori [17]

Answer:

Step-by-step explanation:

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3 0
2 years ago
Find domain and range -√x-5+10
inysia [295]
When finding the domain of a square root, you have to know that it is impossible to get the square root of 0 or any negative number. since domain is possible x values this means that x cannot be 0 or any number less than 0. However, you can find the square root of the smallest most infinitely small number greater than 0. since an infinitely small number close to zero can not be written out, we must must say that the domain starts at 0 exclusive. exclusive is represented by an open or close parenthesis so in this case the domain starts with:
(0,
we can get the square root of any number larger than 0 up to infinity but infinity can never be reached so it is also exclusive. So so the ending of our domain would be:
,infinity)
So the answer if the square root is only over the x the answer is
(0, infinity)

But if the square root is over the x- 5 then this would brIng a smaller amount of possible x values. since anything under the square root sign has to be greater than 0, you can say that:
(x - 5) > 0
x > 5
Therefore the domain would start at 5 and the answer would be:
(5, infinity)
8 0
3 years ago
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