Answer:
<u>Add 8 to both sides</u>
<u></u><u></u>
Answer:
If the length of a tree's shadow is 35.25 meters. The height of the tree to the nearest hundredth of a meter will be : 11.74m
Given:
Denora height=1.35 meters
Length =35.25 meters
Width =31.2 meters
Height of the tree=x
Proportion:
1.35 : 35.25 :: x : 31.2
Now let's determine the height of the tree:
35.25 - 31.2 / 1.35 = 35.25 / x
4.05 / 1.35 = 35.25 / x
Cross multiply
4.05x = 35.25 × 1.35
4.05x = 47.58
Divide both sides
x = 47.58 / 4.05
<u>x = 11.74</u>
In conclusion, if the length of a tree's shadow is 35.25 meters. The height of the tree to the nearest hundredth of a meter will be: 11.74m
Answer:
27 hundredths
Step-by-step explanation:
.2 is in the tenths place,
.07 is in the hundredth place,
.27 is 27 hundredths
Answer:
The correct answer is option c) (5,0) and (5,-2)
Step-by-step explanation:
In the option c the coordinates of two points lie on x= 5
When we substitute the required points in graph we can see clearly that the coordinates of two points lie on x = 5
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Let be A(2,2) and B(4, 4) two points, let be C the point which is on the perpendicular bisector of the segment AB, so the coordinate of C must be
C(2+4 / 2, 2 + 4 /2) = C(3,3)
<span>C is equidistant from the endpoints of the segment.
proof
vect AC= (1, 1), and vect CB= (1, 1), the length of each vect is
CB= sqrt2, and AC=</span>sqrt2, so it is prooved that AC=CB, C is equidistant to the two endpoints