One number (a) exceeds another number (b) by 11 so
a = b+11
a + b = 77
Substitute the equation for a into the second equation
(b+11) + b = 77
multiply each side by 1 to remove parentheses
b + 11 + b = 77
Combine like terms
2b + 11 = 77
Isolate the variable
2b = 77-11
Simplify
2b = 66
Divide by 2
b = 33
Now substitute b back into the initial equation for a
a = (33) + 11
a = 44
Check your work by substituting both values into the second equation
44 + 33 = 77
This is true, so 44 and 33 are solutions
Answer:
x = 8
Step-by-step explanation:
since the triangle is isosceles then the 2 legs are congruent, that is both 4x - 3
the perimeter is the sum of the 3 sides , that is
x + 4x - 3 + 4x - 3 = 66
9x - 6 = 66 ( add 6 to both sides )
9x = 72 ( divide both sides by 9 )
x = 8
Answer:
776
Step-by-step explanation:
To solve this, you first need to convert the fractional percentage into a decimal. 
. Now, you can divide the first number by this number to find what number you would have to multiply this by. 
. Hope this helps!
Answer:
The length of segment DA is 15 units
Step-by-step explanation:
- <em>The segment which joining a vertex of a triangle and the midpoint of the opposite side to this vertex is called a median </em>
- <em>The point of intersection of the median of a triangle divides each median into two parts the ratio between them is 1: 2 from the base, which means </em><em>the length of the median is 3 times the part from the base</em><em> </em>
Let us use this rule to solve the question
In Δ AEC
∵ D is the midpoint of EC
∴ AD is a median
∵ B is the midpoint of AC
∴ EB is a median
∵ F is the midpoint of AE
∴ CF is a median
→ The three medians intersected at a point inside the triangle,
let us called it M
∵ AD ∩ EB ∩ CF at M
∴ M is the point of intersection of the medians of Δ AEC
→ By using the rule above
∴ AD = 3 MD
∵ MD = 5
∴ AD = 3(5)
∴ AD = 15 units
