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KatRina [158]
2 years ago
8

Emilio bought 5.65 of green grapes and 3.07 pounds of red grapes

Mathematics
1 answer:
NISA [10]2 years ago
5 0

The weight of each bag is 0.545 lb .

<h3>What is weight ?</h3>

Weight in maths is the value of the mass of an object on a measuring scale , It is measured in pound , ounce , kilogram etc.

It is given that

Total weight of green grapes = 5.65 lb

Total weight of red grapes = 3.07lb

Total weight = 5.65 +3.07 = 8.72   lb

Total number of bags = 16

the weight of each bag

= 8.72 / 16

= 0.545 lb

Therefore the weight of each bag is 0.545 lb .

The complete question is

Emilio bought 5.65lb  of green grapes and  3.07lb of red grapes. He divided the grapes equally into 16 bags. If each bag of grapes has the same weight, how much does each bag weigh?

To know more about Weight

brainly.com/question/10069252

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That would be simplified into

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3 years ago
Three more than 8 times a number is 29. Find the number.
yanalaym [24]
Well, first off, to solve for this, we can write the expression and then solve from there.
Expression: 8x + 3 = 29
So, now that we have our expression, we can solve for our missing number using the balancing method.
8x + 3 = 29
8x + 3 - 3 = 29 - 3 (we subtracted the three because we needed to get rid of the three on the left side of the equation do now we are just left with 8x = 26.
8x = 26
8x/8 = 26/8. (So, the 8 on the left side cancels out and we are just left with X.
X = 26/8
X = 13/4
X = 3 and 1/4
So, in conclusion, the answer to this question is: X = 3 and 1/4 as a mixed number or 13/4 as an improper fraction.
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3 years ago
Simplify 3(2x^4*y^5)^2/(6x^3*y^3)^6
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\dfrac{3(2x^4y^5)^2}{(6x^3y^3)^6}\qquad\text{use}\ (ab)^n=a^nb^n\ \text{and}\ (a^n)^m=a^{nm}\\\\=\dfrac{3(2^2)(x^4)^2(y^5)^2}{6^6(x^3)^6(y^3)^6}=\dfrac{3(4)x^8y^{10}}{46656x^{18}y^{18}}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\dfrac{12x^8y^{10}}{46656x^8x^{10}y^{10}y^8}=\dfrac{1}{3888x^{10}y^8}

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Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x.
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ANSWER

See below

EXPLANATION

Given

f(x) =  \frac{ {x}- 9 }{x + 5}

and

g(x) =   \frac{ - 5x - 9}{x - 1}

(f \circ \: g)(x)=  \frac{ (\frac{ - 5x - 9}{x - 1})- 9 }{(\frac{ - 5x - 9}{x - 1} )+ 5}

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9 - 9(x - 1)}{x - 1}}{\frac{ - 5x - 9 + 5(x - 1)}{x - 1} }

Expand:

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9 - 9x  + 9}{x - 1}}{\frac{ - 5x - 9 + 5x - 5}{x - 1} }

(f \circ \: g)(x)=  \frac{ \frac{ - 5x - 9x  + 9 - 9}{x - 1}}{\frac{ - 5x + 5x - 5 - 9}{x - 1} }

(f \circ \: g)(x)=  \frac{ \frac{ - 14x }{x - 1}}{\frac{ -14}{x - 1} }

Since the denominators are the same, they will cancel out,

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Which statement describes the equation below?
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Answer:

Abccd

Step-by-step explanation:

Hi low hin

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