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KatRina [158]
2 years ago
8

Emilio bought 5.65 of green grapes and 3.07 pounds of red grapes

Mathematics
1 answer:
NISA [10]2 years ago
5 0

The weight of each bag is 0.545 lb .

<h3>What is weight ?</h3>

Weight in maths is the value of the mass of an object on a measuring scale , It is measured in pound , ounce , kilogram etc.

It is given that

Total weight of green grapes = 5.65 lb

Total weight of red grapes = 3.07lb

Total weight = 5.65 +3.07 = 8.72   lb

Total number of bags = 16

the weight of each bag

= 8.72 / 16

= 0.545 lb

Therefore the weight of each bag is 0.545 lb .

The complete question is

Emilio bought 5.65lb  of green grapes and  3.07lb of red grapes. He divided the grapes equally into 16 bags. If each bag of grapes has the same weight, how much does each bag weigh?

To know more about Weight

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Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel
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Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

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\frac{40}{400}=0.10

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

P(X=x)=^nC_xp^x(1-p)^{n-x}

We need to find P(X ≤ 3)

P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\

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Graph the funxtion y=|x+2|-3
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Your answer would be.........................................
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Find the first term and the common ratio <br>third term =6 and seventh term= 96​
mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: a_n= a_1r^{n-1}

We are given: third term = 6 i,e

a_3=a_1r(3-1)\\6=a_1r^2----eq(1)

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Dividing eq(2) and eq(3)

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So, Common Ratio r = 2

Finding First term using eq(1)

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So, First term a₁ = 3/2 and common ratio r = 2

6 0
3 years ago
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