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Nadusha1986 [10]
3 years ago
15

Need help with this

Mathematics
1 answer:
Alecsey [184]3 years ago
8 0

\frac{x {}^{3}  - 3x {}^{2} - 10x {}^{2} + 30x + 4x - 12  }{x - 3 }  \\  \frac{x {}^{2} \times (x - 3) - 10x \times (x - 3) + 4 \times (x - 3) }{x - 3}  \\  \frac{(x - 3)(x  {}^{2}  - 10x + 4 )}{x - 3}  \\ x {}^{2}  - 10x + 4
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Suppose the heights of women at a college are approximately Normally distributed with a mean of 65 inches and a population stand
Zigmanuir [339]

Answer:

Step-by-step explanation:

Hello!

The variable of interest, X: height of women at a college, has an approximately normal distribution with mean μ= 65 inches and standard deviation σ= 1.5 inches.

You need to look for the value of height that marks the bottom 20% of the distribution, i.e. the height at the 20th percentile of the normal curve, symbolically:

P(X≤x₀)= 0.20

To know what value of height belongs to the 20% of the distribution, you have to work using the standard normal distribution and then reverse the standardization with the population mean and standard deviation to reach the value of X. So the first step is to look for the Z-value that accumulates 20% of the distribution:

P(Z≤z₀)=0.20

z₀= -0.842

z₀= (x₀-μ)/σ

z₀*σ= (x₀-μ)

x₀= (z₀*σ)+μ

x₀= (-0.842*1.5)+65

x₀= 63.737 inches

I hope it helps!

6 0
3 years ago
Read 2 more answers
A famous instance of variation is Newton’s Law of Gravity. It states that the magnitude of the Force, F, of gravitational attrac
adelina 88 [10]

\bf \qquad \qquad \textit{combined proportional variation} \\\\ \begin{array}{llll} \textit{\underline{y} varies directly with \underline{x}}\\ \textit{and inversely with \underline{z}} \end{array}\implies y=\cfrac{kx}{z}\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ F=\cfrac{k(m_1\cdot m_2)}{r^2}\leftarrow \textit{F varies directly with a product and inversely with }r^2

5 0
3 years ago
Guys please help me I don’t understand and my test is due at 12 I only have 40min HELP GREATLY APPRECIATED!!!
ICE Princess25 [194]

Answer:

{9} Slope: -1

Y-intercept = 0

Step-by-step explanation:

Slope-----

Recall slope-intercept form

y=mx+b, with slope m and a y-intercept of b. With this in mind, we can rewrite our equation as y=−x+0

We see that our slope, or coefficient on x, is −1.

Y-intercept-----

We can rewrite this equation as:y=1x+0

The slope-intercept form of a linear equation is: y=mx+b

Where m is the slope and b is the y-intercept value.

For this equation:y=1x+0

Therefore:

The slope is m=1

The y-intercept is b=0 or (0,0)

Hope this helps!

3 0
3 years ago
How many solutions does the absolute value equation have?<br><br> I x - 3 I + 2 = -2
choli [55]

9514 1404 393

Answer:

  the correct answer is marked

Step-by-step explanation:

When the graph of the left side of the equation does not intersect the graph of the right side of the equation, there are no solutions.

__

<em>Additional comment</em>

Even if you extend the domain to complex numbers, there are no solutions. The f(x) = |x| function always returns a positive real value, even for complex numbers.

4 0
3 years ago
Find the exact value of cos (u-v) given that sin u=-9/41 and cos v=15/17. (Both u and v are in quadrant IV)
siniylev [52]
Please review the sum and difference formulas for the trig functions.

In this case you have the difference between two angles u and v and want to find the cosine of this difference.

Here's the appropriate formula:  

cos (a-b) = cos a cos b + sin a sin b

Given that sin u = -9/41, equal to the opp side over the hyp., we must find the length of the adj. side and then u itself.

opp side = - 9
hyp =           4
adj side = sqrt( 18+4) = sqrt(22)

Find the side opp angle v in a similar manner.

Then cos (u-v) = cos u cos v + sin u sin v becomes

                        = (cos u)(15/17) + (-9/41)(sin v)   (where you must find cos u and sin v)

See what you can do, then return and comment here if you need further help.  Good luck.

8 0
4 years ago
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