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egoroff_w [7]
2 years ago
15

Given that (7-2x),9,(5x+17) are consecutive terms of a geometric progression with common ratio, r>0, find the value of x.

Mathematics
1 answer:
andre [41]2 years ago
6 0

This are also referred to as exponential sequence.  The common ratio if r > 0 is 2

<h3>Geometric sequence</h3>

This are also referred to as exponential sequence. Given the following sequence

(7-2x),9,(5x+17)

If they are in geometric progression, hence;

9/7-2x = 5x+17/9

Cross multiply

7-2x(5x+17) = 9(9)

Expand

35x+119-10x²-34x = 81

-10x²+x+119-81=0
10x²-x-38 = 0

Factorize

10x²-20x +19x-38 = 0

10x(x-2)+19(x-2)= 0

x - 2 = 0

x = 2

Hence the common ratio if r > 0 is 2

Learn more on geometric sequence here: brainly.com/question/1509142

#SPJ1

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(2x² - 5x + 3)(4x³ - 1)

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hope this helps
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