NEED HELP ASAP PLEASE . End of quarter today

Beverly is painting a mural on a 1-square-meter section of a wall. She has completed a rectangular part of the mural that's is 5

yawa3891 [41]

Answer:

0.21 square meter

Step-by-step explanation:

Area of the section of wall = 1 square meter

Dimension of part of mural completed = $\frac{1}{4}$ meter by $\frac{5}{6}$ meter

Part of the mural completed = Area of the rectangular part of mural completed

But,

Area of a rectangle = length x width

So that,

Part of the mural completed = length x width

= $\frac{1}{4}$ x $\frac{5}{6}$

= $\frac{5}{24}$

= 0.2083

Part of the mural completed = 0.21 square meter

The part of the mural that has been completed by Beverly is 0.21 square meter.

7 0

2 years ago

Read 2 more answers

Find the sum of the positive integers less than 200 which are not multiples of 4 and 7

taurus [48]

Answer:

$12942$ is the sum of positive integers between $1$ (inclusive) and $199$ (inclusive) that are not multiples of $4$ and not multiples $7$ .

Step-by-step explanation:

For an arithmetic series with:

$a_1$ as the first term,
$a_n$ as the last term, and
$d$ as the common difference,

there would be $\displaystyle \left(\frac{a_n - a_1}{d} + 1\right)$ terms, where as the sum would be $\displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n)$ .

Positive integers between $1$ (inclusive) and $199$ (inclusive) include:

$1,\, 2,\, \dots,\, 199$ .

The common difference of this arithmetic series is $1$ . There would be $(199 - 1) + 1 = 199$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}$ .

Similarly, positive integers between $1$ (inclusive) and $199$ (inclusive) that are multiples of $4$ include:

$4,\, 8,\, \dots,\, 196$ .

The common difference of this arithmetic series is $4$ . There would be $(196 - 4) / 4 + 1 = 49$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}$

Positive integers between $1$ (inclusive) and $199$ (inclusive) that are multiples of $7$ include:

$7,\, 14,\, \dots,\, 196$ .

The common difference of this arithmetic series is $7$ . There would be $(196 - 7) / 7 + 1 = 28$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}$

Positive integers between $1$ (inclusive) and $199$ (inclusive) that are multiples of $28$ (integers that are both multiples of $4$ and multiples of $7$ ) include:

$28,\, 56,\, \dots,\, 196$ .

The common difference of this arithmetic series is $28$ . There would be $(196 - 28) / 28 + 1 = 7$ terms. The sum of these integers would thus be:

$\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}$ .

The requested sum will be equal to:

the sum of all integers from $1$ to $199$ ,
minus the sum of all integer multiples of $4$ between $1\!$ and $199\!$ , and the sum integer multiples of $7$ between $1$ and $199$ ,
plus the sum of all integer multiples of $28$ between $1$ and $199$ - these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

$19900 - 4900 - 2842 + 784 = 12942$ .

8 0

2 years ago

HELP!!! A plumber charges a fee of $25 plus $30 per hour on the job. Make a table of values for the total charge depending on th

Effectus [21]

Answer:

Yes, this function can be defined by linear model.

Step-by-step explanation:

$\mathrm{Total\:=\:Fixed\:Fee\:+\:Hourly\:Rate\:\times Number\:of\:hours}$

$\mathrm{Linear:}\:\:T=\:$25+30h$

Best Regards!

3 0

2 years ago

Itzik 45 seconds to fill an 18 down container how long will it take to fill a 40 gallon container

Akimi4 [234]

When answering this question, I'm assuming "18 down" means 18 gallons
To find the answer, we can divide:
40/18 = 5
( This basically means that there are 5 containers in the 40 gallon container)
knowing this:
45*5 = 225
(Basically solves the time to fill 5 containers)
It will take 225 seconds

4 0

2 years ago

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Clark made four of his truck payments late and was fined four late fees. The total change to his savings from late fees was-$40.

luda_lava [24]

You would do 40 ÷ 4 which would be 10. so it was $10 per late fee

3 0

2 years ago