All categories

2 years ago

What is the rule of the reflection?

Mathematics

1 answer:

iogann1982 [59]2 years ago

8 0

The rule of reflection in the image shown is: (x, -y).

<h3>What is Reflection?</h3>

Reflection is a transformation which creates a new image by flipping over a line of reflection. The new image is congruent to the original image after reflection. The rule of reflection over an x-axis is given as, (x, -y).

In the image given we can see that rotating triangle LMN over the x-axis gave us:

M(-5, 4) → M'(-5, -4)

L(-4, 2) → L'(-4, -2)

N(-2, 3) → N'(-2, -3)

Therefore, the rule of reflection is: (x, -y).

Learn more about reflection on:

brainly.com/question/26642069

#SPJ1

You might be interested in

Simplify : 4y^2+12y-40\y^2+2y-8

PSYCHO15rus [73]

2(2y^4 + 7y^3 - 4y^2 -20)
___________________
Y^2

4y^2 - 40/y^2 + 14y - 8

2(-2y^4 - 7y^3 + 4y^2 + 20)
_ _____________________
Y^2

8 0

3 years ago

Find the angle of least nonnegative measure, θC, that is coterminal with θ=<br> 9π/4.

Lostsunrise [7]

9514 1404 393

Answer:

θC = π/4

Step-by-step explanation:

To find the desired angle, subtract multiplies of 2π until the angle is in the desired range.

9π/4 -2π = (9-8)π/4 = π/4

The angle θC = π/4 is coterminal with θ = 9π/4.

8 0

2 years ago

What sets does the fraction -4/9 belong to?

atroni [7]

Real number, rational number

6 0

3 years ago

The radius r(t)r(t)r, (, t, )of the base of a cylinder is increasing at a rate of 111 meter per hour and the height h(t)h(t)h, (

sp2606 [1]

Answer:

The volume is decreasing at a rate 20π cubic meter per hour.

Step-by-step explanation:

We are given the following in the question:

The radius is increasing at a rate 1 meter per hour.

$\dfrac{dr}{dt} = 1\text{ meter per hour}$

The height is decreasing at a rate 4 meter per hour

$\dfrac{dh}{dt} = -4\text{ meter per hour}$

At an instant time t,

r = 5 meter

h = 8 meters

Volume of cylinder =

$\pi r^2 h$

where r is the radius and h is the height of the cylinder.

Rate of change of volume is given by:

$\dfrac{dV}{dt} = \dfrac{d(\pi r^2 h)}{dt}\\\\\dfrac{dV}{dt} = 2\pi rh\dfrac{dr}{dt} + \pi r^2\dfrac{dh}{dt}$

Putting all the values we get,

$\dfrac{dV}{dt} = 2\pi (5)(8)(1) + \pi (5)^2(-4)\\\\\dfrac{dV}{dt} = 80\pi - 100\pi = -20\pi \approx -62.8$

Thus, the volume is decreasing at a rate 20π cubic meter per hour or 62.8 cubic meter per hour.

3 0

3 years ago

Please solve I will mark brainliest if correct

VladimirAG [237]

Answer:

m<RQP = 62°

Step-by-step explanation:

m<RQP = m<PQB + m<RQB

m<RQP = 38° + 24°

m<RQP = 62°

6 0

3 years ago