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worty [1.4K]
3 years ago
6

X^2-8x-36=0 solve by completing the square ANSWER ASAP

Mathematics
1 answer:
larisa86 [58]3 years ago
7 0

Answer:

hope it helps

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SOMEONE HELP PLEASE NEED ANSWER ASAP!!!
shepuryov [24]

Answer:

3

Step-by-step explanation:

=12/4

the common ratio =3

3 0
3 years ago
If 10 is reduced by 4 times what will be the answer??<br> I'm bit confused.....help me out....
babunello [35]
I don't really understand the question
3 0
3 years ago
Suppose that salaries for recent graduates of one university have a mean of $25,700 with a standard deviation of $1350. Using Ch
sergeinik [125]

Answer:

75% of the data will reside in the range 23000 to 28400.

Step-by-step explanation :

To find the range of values :

We need to find the values that deviate from the mean. Since we want at least 75% of the data to reside between the range therefore we have,

1 - \frac{1}{k^2} =\frac{75}{100}

Solving this, we would get k = 2 which shows the value one needs to find lies outside the range.

Range is given by : mean +/- (z score) × (value of a standard deviation)  

⇒ Range : 25700 +/- 2 × 1350

⇒ Range : (25700 - 2700) to (25700 + 2700)

Hence, 75% of the data will reside in the range 23000 to 28400.

3 0
3 years ago
Need help with school work
vichka [17]
15^2 + 36^2 = 39^2

Your answer is 39
3 0
3 years ago
Read 2 more answers
Hi I'm the mom I would like to see if you can help me with this problem
Tanya [424]

From the statement of the problem, we know that:

• a train starts at City A and travels 2,158 km to City B,

,

• then it travels 3,793 km from City B to City C.

The distance between City A and City C is equal to the sum of the distance from City A to City B, and the distance from City B to City C. So the distance between City A and City C is 2,158 km + 3,793 km = 5951 km.

Looking at the answer of Clay:

<em>2,158 + 3,793 = (2,158 + 7) + (3,793 + 7) = 2,165 + 3,800 = 5,965</em>

We see that he added 7 km to each of the distances, that's the reason why he found a different a wrong result.

5 0
1 year ago
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