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3 years ago

10

What is 5500 divided by 785

2 answers:

Mariana [72]3 years ago

8 0

Answer:

785 Remainder 5

Step-by-step explanation:

coldgirl [10]3 years ago

7 0

I thinkkkkk ur answer is going to be 98

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4 teammates shAre 5 granola bars equally draw to show how much each person gets shade the amount that one person gets

Artyom0805 [142]

Each person would get 1/5 beacuse you would have to divide 5 into 4.

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3 years ago

Your teacher gives you the problem 5 ➗ 1/4. Write a story problem to represent 5 ➗ 1/4. Solve your story problem.

worty [1.4K]

Answer:

diego has 1/4 of a brownie tray left to split amongst his 5 friends, how many brownies will each friend get?(0.05)

Step-by-step explanation:

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3 years ago

What is the percent of change from 88 to 92

Helga [31]

Subtract. 92-88=Percent change
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4 years ago

Use the variation of parameters method to solve the DR y" + y' - 2y = 1

postnew [5]

Answer:

$y(t)\ =\ C_1e^{-2t}+C_2e^t-t\dfrac{e^{-2t}}{3}-\dfrac{1}{3}$

Step-by-step explanation:

As given in question, we have to find the solution of differential equation

$y"+y'-2y=1$

by using the variation in parameter method.

From the above equation, the characteristics equation can be given by

$D^2+D-2\ =\ 0$

$=>D=\ \dfrac{-1+\sqrt{1^2+4\times 2\times 1}}{2\times 1}\ or\ \dfrac{-1-\sqrt{1^2+4\times 2\times 1}}{2\times 1}$

$=>\ D=\ -2\ or\ 1$

Since, the roots of characteristics equation are real and distinct, so the complementary function of the differential equation can be by

$y_c(t)\ =\ C_1e^{-2t}+C_2e^t$

Let's assume that

$y_1(t)=e^{-2t}$ $y_2(t)=e^t$

$=>\ y'_1(t)=-2e^{-2t}$ $y'_2(t)=e^t$

and g(t)=1

Now, the Wronskian can be given by

$W=y_1(t).y'_2(t)-y'_1(t).y_2(t)$

$=e^{-2t}.e^t-e^t(-e^{-2t})$

$=e^{-t}+2e^{-t}$

$=3e^{-t}$

Now, the particular solution can be given by

$y_p(t)\ =\ -y_1(t)\int{\dfrac{y_2(t).g(t)}{W}dt}+y_2(t)\int{\dfrac{y_1(t).g(t)}{W}dt}$

$=\ -e^{-2t}\int{\dfrac{e^t.1}{3.e^{-t}}dt}+e^{t}\int{\dfrac{e^{-2t}.1}{3.e^{-t}}dt}$

$=\ -e^{-2t}\int{\dfrac{1}{3}dt}+\dfrac{e^t}{3}\int{e^{-t}dt}$

$=\dfrac{-e^{-2t}}{3}.t-\dfrac{1}{3}$

$=-t\dfrac{e^{-2t}}{3}-\dfrac{1}{3}$

Now, the complete solution of the given differential equation can be given by

$y(t)\ =\ y_c(t)+y_p(t)$

$=C_1e^{-2t}+C_2e^t-t\dfrac{e^{-2t}}{3}-\dfrac{1}{3}$

5 0

3 years ago

There is a Chick-fil-a exactly 6 miles due east of Berkmar Middle School. There is also a Wal-Mart 6 miles due north of Berkmar

Vedmedyk [2.9K]

Answer:

6√2 miles

Step-by-step explanation:

Using the solution diagram drawn :

We have a right angled triangle, the distance between Walmart mad chick-FIL is a measure of the hypotenus of the right angled triangle ;

The hypotenus, = √(opposite² + adjacent²)

Hypotenus = √6² + 6²

Hypotenus = √(36 + 36)

Hypotenus = √72

Hypotenus = √36 * 2 = √36 * √2 = 6√2 miles

5 0

3 years ago