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Delicious77 [7]
3 years ago
11

Find the sum to infinity of the series 2+5/4+11/16+23/64+..........up to the infinity.

Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0

We have

2+\dfrac54+\dfrac{11}{16}+\dfrac{23}{64}+\cdots=\displaystyle\sum_{n=0}^\infty\frac{3\cdot2^n-1}{4^n}

(notice that each denominator is a power of 4, and each numerator is one less than some multiple of 3, in particular 3 times some power of 2)

Recall for |x|, we have

\displaystyle\frac1{1-x}=\sum_{n=0}^\infty x^n

So we have

\displaystyle\sum_{n=0}^\infty\frac{3\cdot2^n-1}4=3\sum_{n=0}^\infty\left(\frac12\right)^n-\sum_{n=0}^\infty\left(\frac14\right)^n=\frac3{1-\frac12}-\frac1{1-\frac14}=\boxed{\frac{14}3}

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