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Ray Of Light [21]
1 year ago
10

15. How many PC’s can be connected to a UPS?

Computers and Technology
1 answer:
Alex_Xolod [135]1 year ago
6 0

Answer: Depends on the power of the computer /computers and the UPS

Explanation: For someone who had a big connected network of computers and printers we would plug the computer or server into the UPS as well as the monitor and sometimes a printer sometimes the monitor was plugged into the wall

When you get a UPS you must plug it in for a certain time could be hours or even a day.  A USP has a big battery in it and you must charge it (sometimes it comes semi-charged but you must plug it in to strengthen it. )

there are two connector wires that you affix to the battery and you must put a lot of strength into it to make it secure.

So in closing, you can get away with two like a desktop and a laptop.

Read your documentation that comes with the UPS

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Hi,

I believe it's "show".

"To show the navigation pane if it's hidden,
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r3t40
4 0
3 years ago
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The variable used in a loop to control the number of times it is executed is called a _______.
tia_tia [17]

Answer:

the variable used in a loop to control the number of timer is executed is called a interaction.

Explanation:

a particular way in which matter, fields, and atomic and subatomic particles affect one another

6 0
3 years ago
Create the following SQL Server queries that access the Northwind database. Place them in a zip file and place the zip file in t
neonofarm [45]

Answer:

1. SELECT e.EmployeeID, e.FirstName, e.LastName, COUNT(*) as OrderByEmployee FROM Employees e

JOIN Orders o

ON e.EmployeeID = o.EmployeeID

WHERE YEAR(o.OrderDate) = '1996'

GROUP BY e.EmployeeID,e.FirstName,e.LastName

ORDER BY OrderByEmployee DESC

2. SELECT o.OrderID,c.CustomerID, o.OrderDate,SUM((od.Quantity)*

od.UnitPrice - od.Discount)) as TotalCost FROM Orders o

JOIN [Order Details] od

ON od.OrderID = o.OrderID

JOIN Customers c

ON o.CustomerID = c.CustomerID

WHERE (MONTH(OrderDate)= 7 OR MONTH(OrderDate) = 8) and

YEAR(OrderDate) = 1996

GROUP BY o.OrderID,c.CustomerID, o.OrderDate

ORDER BY TotalCost DESC

3. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

ORDER BY c.City, c.CustomerID

4. SELECT c.CustomerID, c.CompanyName, c.City, COUNT(o.OrderID) as TotalOrder, SUM(od.Quantity* od.UnitPrice) as TotalOrderAmount FROM Customers c

JOIN Orders o

ON o.CustomerID = c.CustomerID

JOIN [Order Details] od

ON od.OrderID = o.OrderID

WHERE c.Country = 'USA'

GROUP BY c.CustomerID, c.CompanyName, c.City

HAVING COUNT(o.OrderID) > 3

ORDER BY c.City, c.CustomerID

5. SELECT p.ProductID, p.ProductName, s.ContactName as SupplierName, MAX(o.OrderDate) as LastOrderDateOfProduct FROM Products p

JOIN Categories c

ON c.CategoryID = p.CategoryID

JOIN Suppliers s

ON s.SupplierID = p.SupplierID

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

where c.CategoryName = 'Grains/Cereals'

GROUP BY p.ProductID, p.ProductName, s.ContactName

ORDER BY SupplierName, p.ProductName

6. SELECT p.ProductID, p.ProductName, Count(DISTINCT c.CustomerID ) as OrderByThisManyDistinctCustomer

FROM Products p

JOIN [Order Details] od

ON od.ProductID = p.ProductID

JOIN Orders o

ON o.OrderID = od.OrderID

JOIN Customers c

ON c.CustomerID = o.CustomerID

where YEAR(o.OrderDate) = 1996

GROUP BY p.ProductID, p.ProductName

Explanation:

The six query statements returns data from the SQL server Northwind database. Note that all the return data are grouped together, this is done with the 'GROUP BY' Sql clause.

8 0
3 years ago
Please help me idk I suck at this stuff ​
kap26 [50]
I would say the best clear answer is D, because A is a little bit unclear but I would say the best answer is D.

Why?

Mesh Topology is expensive considering more links as compared to Ring topology.


4 0
2 years ago
I will give 100 points
UkoKoshka [18]

Answer:

sibling, fritend, or fellow styu346yhtwf vrrrrrrrgqreg t5

3 0
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