En un blog se habla de una cosa en específico y en una página web puedes buscar diferentes temas
ESPERO Y TE AYUDE ;)
Answer:
Option B i.e., False.
Explanation:
The weakness, KRACK tricks a wifi access points to reuse an in-use encryption, enabling the intruder to decode and interpret data intended to remain encrypted. Wireless communication encrypts, that decrypt unencrypted wireless network activity and expose sensitive data.
So, the following scenario is false about the wireless attack.
Answer:
Following are the algorithm to this question:
y = 0 // initialize variable y that assigns the value 0
p = 1 // initialize value 1 in the variable p which also known as starting position
init num = 1//define variable num that assign value 1
for j = 1 to n: //defining loop
y = m[j] - m[p]
if (y > 10) //defining if block
num++; //increment num variable
p=i; //holding loop value in p variable
y= 0//assign value 0 in y variable
Explanation:
Following are the runtime analysis of the above-given algorithm:
The above-provided algorithm is greedy, but if it doesn't exceed the scope, it operates by greedily choosing its next object. Therefore the algorithm selects the fewest number of pens.
Running time:
This algorithm merely iterates once over all the points. The run-time is therefore O(n).
Answer:
The function in Python is as follows:
def d2x(d, x):
if d > 1 and x>1 and x<=9:
output = ""
while (d > 0):
output+= str(d % x)
d = int(d / x)
output = output[::-1]
return output
else:
return "Number/Base is out of range"
Explanation:
This defines the function
def d2x(d, x):
This checks if base and range are within range i.e. d must be positive and x between 2 and 9 (inclusive)
if d >= 1 and x>1 and x<=9:
This initializes the output string
output = ""
This loop is repeated until d is 0
while (d > 0):
This gets the remainder of d/x and saves the result in output
output+= str(d % x)
This gets the quotient of d/x
d = int(d / x) ----- The loop ends here
This reverses the output string
output = output[::-1]
This returns the output string
return output
The else statement if d or x is out of range
<em> else:</em>
<em> return "Number/Base is out of range"</em>
<em />
First things first you have to do write it down which you did
step 2: then you multiply each digit of the binary number by the corresponding power of 2: 1x25 + 0x24 + 1x23 + 1x22 + 0x21 + 1x2 0
step 3: solve the powers: 1x32 + 0x16 + 1x8 + 1x4 + 0x2 + 1x1 = 32 + 0 + 8 + 4 + 0 + 1
step 4: add the numbers written above
32 + 0 + 8 + 4 + 0 + 1 = 45.
So, 45 is the decimal equivalent of the binary number 101101.
