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4 years ago

9

Find the surface area of the prism. A 75 cm^2 B 125 cm^2 C 95 cm^2 D 113 cm^2

1 answer:

Sav [38]4 years ago

3 0

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Find the product (3x+8)(x-4)

timurjin [86]

Answer:

3 $x^{2}$ - 4x - 32

Step-by-step explanation:

(3x+8)(x-4)

=3 $x^{2}$ -12x + 8x -32

=3 $x^{2}$ - 4x - 32

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3 years ago

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What is the 11th term of the sequence: 7, 13, 19, 25, ....

wel

pattern is adding 6

so the 11th would be 67

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3 years ago

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Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

Alekssandra [29.7K]

In the given figure we can determine the coordinate of point M from the graph, we get:

$M=(\frac{d}{2},\frac{c}{2})$

We can also determine the coordinates of point N as:

$N=(\frac{a+b}{2},\frac{c}{2})$

Now, to determine the length of segment MN, we need to subtract the x-coordinate of M from the coordinates of N, we get:

$MN=\frac{a+b}{2}-\frac{d}{2}$

Subtracting the fractions we get:

$MN=\frac{a+b-d}{2}$

Now, to obtain the length of AB we need to subtract the x-coordinate of A from the x-coordinate of B.

The coordinates of A are determined from the graph:

$A=(0,0)$

The coordinates of B are:

$B=(a,0)$

Therefore, the length of segment AB is:

$AB=a$

Now we do the same procedure to determine the segment of CD. The coordinates of C are:

$C=(b,c)$

The coordinates of D are:

$D=(d,c)$

Therefore, CD is:

$CD=b-d$

Now, we determine MN as half the sum of the bases. The bases are AB and CD, therefore:

$MN=\frac{1}{2}(a+b-d)$

Therefore, we have proven that the median of a trapezoid equals half the sum of its bases.

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1 year ago

Un depósito abierto tiene la forma de un cono circular recto Un depósito abierto tiene la forma de un cono circular recto. El de

balu736 [363]

i do not speak spanish

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3 years ago

The ratio of the number of Victor’s tools to the number of Ilya’s tools is 5:2. Victor has 42 more tools than Ilya. How many too

irga5000 [103]

Answer:

Victor gives 28 tools to IIya.

Step-by-step explanation:

Consider the provided information

The ratio of the number of Victor’s tools to the number of Ilya’s tools is 5:2

Let V represents the Victor and I represent llya

Therefore,

$\frac{V}{I} = \frac{5}{2}$

It is given that Victor has 42 more tools than Ilya.

$\frac{V}{I} = \frac{5}{2}=\frac{42+I}{I}$

Solve the above equation.

$\frac{5}{2}=\frac{42+I}{I}$

$5I=84+2I$

$3I=84$

$I=28$

Thus, IIya has 28 tools.

Victor has 42 more tools than Ilya. Therefore 42 + 28 = 70.

Victor has 70 tools.

We want to find the number of tools victor needs to give to IIya so that the ratio of the number of Victor's tools to the number of Ilya’s tools will be 3:4

Let Victor gives x tools to IIya. Thus,

$\frac{3}{4}=\frac{70-x}{28+x}$

$3(28+x)=4(70-x)$

$84+3x=280-4x$

$7x=196$

$x=28$

Hence, Victor gives 28 tools to IIya.

4 0

3 years ago