On analyzing the question we can say that the angle ∠JKM of the triangle ΔJKL would be 42 as line MK bisects ∠JKL into ∠JKM & ∠MKL.
From the question it follows that line MK bisects angle ∠JKL into ∠JKM & ∠MKL where M is the point in the interior of ∠JKL.
Therefore, as we have given m∠JKL = 84 & m∠MKL = 42
and we have to find m∠JKM , we will simply write the equation as follow
m∠JKL = m∠JKM + m∠MKL
Inserting values we get,
84 = m∠JKM + 42
m∠JKM = 42
Hence, angle m∠JKM of the triangle ΔJKL is 42.
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Answer: ( 11, -2 )
Step-by-step explanation:
The mid point of a line is calculated using the formula:
M = (
, 
)
From the question , the mid point is already given , substituting , we have :
(5 , - 7.5 ) = (
, 
)
Equating the x component to x and the y component to y , we have
5 =
x - 1 = 10
x = 11
Also
- 7.5 =
-15 = y - 13
-15 + 13 = y
Therefore : y = -2
Therefore : the location of point P is ( 11, -2 )
Answer:
140°
Step-by-step explanation:
The sum of angle of a triangle is equal to 180°.
Two of the angles measured 20°.
We need to find the measure of the third angle of Nora’s triangle. let the third angle is x. So,
20+20+x = 180
40+x = 180
x = 180-40
x = 140°
So, the third angle of the triangle is 140°.
Answer: approximately km*1.61=m
Step-by-step explanation:
Answer:
A True
Step-by-step explanation:
tell me if I'm worng
