We want to expand (2x + y²)⁵.
From Pascal's Triangle (shown below), the coefficients of the expansion are
1,5,10,10,5,1.
n=0: 1
n=1: 1 1
n=2: 1 2 1
n=3: 1 3 3 1
n=4: 1 4 6 4 1
n=5: 1 5 10 10 5 1
Therefore the third term in the expansion is
10*(2x)³*(y²)² = 10*(8x³)*(y⁴) = 80x³y⁴
Alternatively, the third term is
₅C₃ (2x)³(y²)² = 10*(8x³)*(y⁴) = 80x³y⁴
Answer: 80x³y⁴
Using the function concept, it is found that f is a function, as each student is related to only one GPA and only one number of credits.
In a function, <u>one value of the input can be related to only one value of the output</u>.
In this problem:
- The input is the student.
- The output is the student GPA, and the number of credits earned.
Each student is related to only one GPA and only one number of credits, hence <u>one value of the input is related to only one value of the output</u>, and f is a function.
To learn more about the function concept, you can take a look at brainly.com/question/12463448
Remark
11 and 3 are both prime. So the common denominator is 33
The correct answer for this question is 4.
We have to bear in mind that any number should be less than 5 to make the square root be an imaginary number.
Starting with 4
= square root (4 - 5)
= square root (-1)
= imaginary
Answer: it will only take jime 30 min
Step-by-step explanation:
