2 years ago

Consider the expression.

Mathematics

1 answer:

lorasvet [3.4K]2 years ago

5 0

Two less than 5 times a number is 9

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HELP ILL GIVE BRAINLIEST

Alex17521 [72]

Y=2x+2 easy
The slop=2/1
Y-int= (0,2)

7 0

3 years ago

Given the following constants for a standard form quadratic equation, determine the nature of its roots. Please wait for photo t

lisabon 2012 [21]

$ax^2+bx+c=0$
$3x^2+3x+2=0$
$D=b^2-4ac=3^2-4*3*2=9-24=-15$
$D$ , so there are no real solutions.

3 0

3 years ago

Can someone help me? it’s due in a few hours

ioda

Answer:

cars value decreases in value exponentially

Step-by-step explanation:

cant really read it but say that the cars value decreases in value exponentially and compare that to however the other cars decrease in value over time

4 0

2 years ago

The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:

deff fn [24]

Step-by-step explanation:

Given equation of circle is,

${x}^{2} + {y}^{2} - 6y - 12 = 0 \\ by \: compairing \: it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f= - 6 \\ or \: f= - 3 \\ c = - 12$

again the another form of circle is,

${x}^{2} + {(y - k)}^{2} = 21 \\ or \: {x}^{2} + {y}^{2} - 2ky + {k}^{2} - 21 = 0 \\ by \: compairing \:it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\ g = 0 \\f = - k \\ c = {k}^{2} - 21$

now equating the values of f in both equations,

-k=-3

i.e. k=3

therefore k=3

4 0

3 years ago

What is the solution set of y = x^2 + 2x + 7 and y = x + 7?

frozen [14]

Answer:

A, I believe

Step-by-step explanation:

7 0

3 years ago