Answer:
Step-by-step explanation:
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Hello,
Vertices are on a line parallele at ox (y=-3)
The hyperbola is horizontal.
Equation is (x-h)²/a²- (y-k)²/b²=1
Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)
Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6
c²=a²+b²==>b²=36-4²=20
Equation is:
Answer:
Step-by-step explanation:

Answer:
3.83
Step-by-step explanation:
Mean of x = Σx / n
Mean of x = (14 + 19 + 13 + 6 + 9) / 5 = 12.2
Sum of square (SS) :
(14-12.2)^2 + (19-12.2)^2 + (13-12.2)^2 + (6-12.2)^2 + (9-12.2)^2 = 98.8
Mean of y = Σy / n
Mean of y = (101 + 89 + 48 + 21 + 47) / 5 = 61.2
Σ(y - ybar)² = (101-61.2)^2 + (89-61.2)^2 + (48-61.2)^2 + (21-61.2)^2 + (47-61.2)^2 = 4348.8
df = n - 2 = 5 - 2 = 3
Σ(y - ybar)² / df = 4348.8 / 3 = 1449.6
√(Σ(y - ybar)² / df) = √1449.6 = 38.074
Standard Error = √(Σ(y - ybar)² / df) / √SS
Standard Error = 38.074 / √98.8
Standard Error = 3.83