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jolli1 [7]
4 years ago
9

How do i do the equation 2+6 divided by 3 divided by 1 with an exponent of 8?

Mathematics
2 answers:
tester [92]4 years ago
8 0

Answer:

4

Step-by-step explanation:

First you need to evaluate the power (exponent).

1 raised to any power is still 1.

Then you need to divide the equation

2 + 6 ÷ 3 ÷ 1

2 + 2

4

Naddika [18.5K]4 years ago
7 0

Answer:

Step-by-step explanation:

To solve this problem you should follow the PEMDAS rule, which is parentheses, exponents, multiplication, division, addition, and subtraction.

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What is 5to the 126th power / 7891262378 *65867587656758764*5546657465848564865465800ret0trer0etr0te0rtew0rt0twr0ewrt0tre0wtrw00
irina1246 [14]

Answer:

1.175494351

Step-by-step explanation:

3 0
3 years ago
Help me please I don’t understand
statuscvo [17]

Answer:

C

Step-by-step explanation:

It says he walked 2(3/4) miles in 2 hours, and it wants to know how far he walked in 1 mile, which would be that number divided by 2.

2(3/4) is the same as 2.75

2.75/2=11/8

which is equivalent to 1(3/8) miles

5 0
3 years ago
Read 2 more answers
Which of the sets of ordered pairs represents a function?
iogann1982 [59]
(x,y)
if x repeats with a differnt y then it is not a function


A. none of them repeat, it's a function
B. none of them repeat, it's a function

both of them are functions
5 0
3 years ago
What is the volume of a rectangular prism with the following dimensions
andriy [413]

Answer: 250ft3

Step-by-step explanation:

v=l*w*H

v= 10*5 * 5

v=250

7 0
4 years ago
Read 2 more answers
If x varies inversely as the square of y and if x=3 when y=-1, what is the value of x when y =3
lyudmila [28]

Answer:

x would be (1/3) when y = 3.

Step-by-step explanation:

The question states that x varies "inversely" as y^2. In other words, there is a non-zero number a (a constant) such that:

\displaystyle x = \frac{a}{y^2}.

The challenging part is to find the value of a in this equation.

Given that x = 3 when y = -1, replace the x in this equation with 3 and y with (-1). This equation should still be valid:

\displaystyle 3 = \frac{a}{(-1)^{2}}.

Solve for a:

a = 3 \times (-1)^2 = 3.

Hence, the relation between x and y becomes:

\displaystyle x = \frac{3}{y^2}.

Find the value of x when y = 3 by replacing the y in this equation with 3.

\displaystyle x = \frac{3}{3^2} = \frac{1}{3}.

In other words, the value of x would be \displaystyle \frac{1}{3} when y = 3.

7 0
3 years ago
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