So to fine slope you would use the formula down below:
rise/run
So use a graphed point, 0, -5 and you rise or count up quadrants up to a point and then horizontally move to when you find that point.
So from 0,-5 go up 9 vertically, and you would be on the 4
Go horizontal 3 spots and your on a designated point.
So the rise is four and the run is 3
So 4/3 is the slope
In the y= Mx + b equation you would set the equation like this:
y= 4/3 + -5
The m in this formula stands for the slop and the b stands for the y-intercept
The y-intercept is the point that is on the y-axis and where it starts.
Answer:
11
Step-by-step explanation:
it says 11
Dale drove to the mountains last weekend. there was heavy traffic on the way there, and the trip took 7 hours. when dale drove home, there was no traffic and the trip only took 5 hours. if his average rate was 18 miles per hour faster on the trip home, how far away does dale live from the mountains? do not do any rounding.
Answer:
Dale live 315 miles from the mountains
Step-by-step explanation:
Let y be the speed of Dale to the mountains
Time taken by Dale to the mountains=7 hrs
Therefore distance covered by dale to the mountain = speed × time = 7y ......eqn 1
Time taken by Dale back home = 5hours
Since it speed increased by 18 miles per hour back home it speed = y+18
So distance traveled home =speed × time = (y+18)5 ...... eqn 2
Since distance cover is same in both the eqn 1 and eqn 2.
Eqn 1 = eqn 2
7y = (y+18)5
7y = 5y + 90
7y - 5y = 90 (collection like terms)
2y = 90
Y = 45
Substitute for y in eqn 1 to get distance away from mountain
= 7y eqn 1
= 7×45
= 315 miles.
∴ Dale leave 315 miles from the mountains
I feel like it’s the last set but then again I haven’t done that kind of math in a few years. Hopefully that helps !