Answer:
b) no solution
Step-by-step explanation:
What you always want to do in this type of problem is to combine all of your "like terms," where like terms are the part of your equation that have the same variable (or no variable). In this equation, we see three terms that have the variable "z". We can add the 12z + 15z on the left side to get 27z, and then we subtract 27z on both sides to cancel both of the 27z terms out.
Now, we are left with -6 = -5 (because we got rid of all the terms with the variable z in them). We know that -6 does not equal -5, and therefore, there is no number that we can assign to variable z such that the left side of the equation will equal the right side of the equation.
Therefore, there is no solution (because a solution to the equation would be a value that we can plug into the variable z to make the equation true).
Answer:
m<PXQ Is Acute
m<QXN is Obtuse
Step-by-step explanation:
Acute Angles are lsss than 90⁰
Obtuse Angles are greater than 90⁰
Right angles are exactly 90⁰
Answer:
HUH!!!??
Step-by-step explanation:
Answer:
$2000 I hope it's helpful for you
T(t)=e−kt(∫ekt[KM(t)+H(t)+U(t)]dt+C)
M is the outside temperature, H is other things that affect temperature
in the tank(0 in this case), and U is the solar panel. K comes from the
time constant, and should be the inverse of the time constant I believe.
T is temperature, t is time.
T(t)=e−164t(∫e164t[164(80)+4t]dt
After integrating I keep getting
−16304+256t+Ce−164t
I calculate C to be 16414 setting t equal to 0 and using the initial conditions