Answer:
int main()
{
int x,y;
bool b1, b2;
cout<<"enter values of x : ";
cin>>x;
cout<<"enter values of y : ";
cin>>y;
b1 = y > x; // false
b2 = x > y; // true
cout << "b1 is = " << b1 << "\n";
cout << "b2 is = " << b2 << "\n";
if (b2)
cout<<endl << "Larger Number" << "\n";
else
cout << "Smaller Number" << "\n";
return 0;
}
Answer:Document the reason for the request, Follow the company’s approval process for the implementation
Explanation:
The port 20 and 21 are used for the FTP connection, so before opening port 20 and 21 it is necessary to abide by the company data security policy which includes documenting the reason for the request and following company's approval process for its implementation.
Answer:
PART ONE
- import java.util.Scanner;
- public class CountToLimit {
- public static void main(String[] args) {
- Scanner scnr = new Scanner(System.in);
- int countLimit = 0;
- int printVal = 0;
- // Get user input
- System.out.println("Enter Count Limit");
- countLimit = scnr.nextInt();
- do {
- System.out.print(printVal + " ");
- printVal = printVal + 1;
- } while ( printVal<=countLimit );
- System.out.println("");
- return;
- }
- }
PART TWO
- import java.util.Scanner;
- public class NumberPrompt {
- public static void main (String [] args) {
- Scanner scnr = new Scanner(System.in);
- System.out.print("Your number < 100: ");
- int userInput = scnr.nextInt();
- do {
- System.out.print("Your number < 100: ");
- userInput = scnr.nextInt();
- }while (userInput>=100);
- System.out.println("Your number < 100 is: " + userInput);
- return;
- }
- }
Explanation:
In Part one of the question, The condition for the do...while loop had to be stated this is stated on line 14
In part 2, A do....while loop that will repeatedly prompt user to enter a number less than 100 is created. from line 7 to line 10
